Question

The slope-intercept form of the equation of a line that passes through point (–3, 8) is y = –x + 6. What is the point-slope form of the equation for this line?
y – 3 = –(x + 8)y + 3 = –(x – 8)y + 8 = –(x – 3)y – 8 = –(x + 3)

Answer 1

The point-slope intercept is y - 8 = -(x + 3).  I think.

Answer 2

Answer:

Option 4 - $y-8=-(x+3)$

Step-by-step explanation:

The slope-intercept form of the equation of a line that passes through point (–3, 8) is $y =-x+ 6$.

The general form of slope intercept is $y=mx+c$

where, m is the slope and c is the y-intercept.

On comparing,

m=-1 and c=6

The point slope form of the equation of a straight line is

$y-y_1=m(x-x_1)$

Point is $(x_1,y_1)=(-3,8)$

Substitute the values,

$y-8=-1(x-(-3))$

$y-8=-(x+3)$

The point-slope form of the equation for this line is $y-8=-(x+3)$

Therefore, Option 4 is correct.