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Slav-nsk [51]
4 years ago
9

A point located at (-3, -4) is reflected over both axes. What are the coordinates of the image?

Mathematics
1 answer:
ollegr [7]4 years ago
3 0
Just reverse the coordinates so it would be (3,-4) hope this helped!
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A street is drawn by dilating segment FG¯ about center A with a scale factor greater than 0 but less than 1. Is this an enlargem
Arte-miy333 [17]

Answer: This is an reduction.

Step-by-step explanation:

  • A dilation a king of transformation that creates an similar image (about a center of dilation) of the actual figure by changing its size with the use of a scale factor(k).
  • It either shrinks or stretches the image.
  1. If |k| is greater than 1 then the image is an enlargement .
  2. If |k| is less than 1 then the image is an reduction.
  3. If |k| is equals to 1 then there is no change in size.

Given : A street is drawn by dilating segment \overline{FG} about center A with a scale factor greater than 0 but less than 1.

Then by using (2.) , we can say that this is an reduction.

5 0
3 years ago
Rectangle PQRS is dilated by a scale factor of 2 (k=2) with the origin as the center. What are the coordinates of R('?
Radda [10]

Answer:

Correct Answer: (8,2)

Step-by-step explanation:

<u>Dilation about the origin</u>

Most dilations in the coordinate plane use the origin, (0,0), as the center of the dilation.

In such cases, every point (x,y) dilated by a factor of k is mapped to the point (kx,ky).

The point R=(4,1) is dilated by a scale factor of 2 (k=2), thus the coordinates of its image are (2*4,2*1) = (8,2)

4 0
3 years ago
Indicate in standard form the equation of the line passing through the given points. X(0, 6), Y(5, 6)
Olegator [25]
(0,6)(5,6)
notice how the y values are they same.....this means u have a horizontal line with a 0 slope.

y = 0x + 6...slope intercept form
0x + y = 6 <==== standard form
8 0
3 years ago
Pls ans.thanks a lot
yawa3891 [41]

Answer:

you're answer is -2

Step-by-step explanation:

i hope this helped you have a nice day  :)

6 0
3 years ago
A golfer exerts a force of 15.0 N on a golf ball that has a mass of 0.42 kg. What is the golf
Gala2k [10]

Answer:

35.71m/s²

Step-by-step explanation:

using the formula force(F)=mass(m)×acceleration(a)

a =

\frac{f}{m}

F=15.0N

m=0.42kg

a=?

a=15÷0.42

a=35.71m/s²

5 0
4 years ago
Read 2 more answers
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