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Olegator [25]
3 years ago
5

Which value of $y$ makes the equation $3y+8=7y+11$ true?

Mathematics
1 answer:
valentinak56 [21]3 years ago
8 0

value of y which satisfies equation 3y+8=7y+11 is  y= \frac{-3}{4} .

<u>Step-by-step explanation:</u>

We have , 3y+8=7y+11 . We need to find which value of y satisfies this equation  3y+8=7y+11 :

3y+8=7y+11

⇒ 3y+8=7y+11

⇒ (3y+8)-3y=(7y+11)-3y

⇒ 8=4y+11

⇒ 4y+11 = 8

⇒ (4y+11)-11 = 8-11

⇒ 4y= -3

⇒ \frac{4}{4}y= \frac{-3}{4}

⇒ y= \frac{-3}{4}

Therefore, value of y which satisfies equation 3y+8=7y+11 is  y= \frac{-3}{4} .

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