Question

Which value of $y$ makes the equation $3y+8=7y+11$ true?

Answer 1

value of y which satisfies equation $3y+8=7y+11$ is  $y= \frac{-3}{4}$ .

Step-by-step explanation:

We have , 3y+8=7y+11 . We need to find which value of y satisfies this equation  3y+8=7y+11 :

$3y+8=7y+11$

⇒ $3y+8=7y+11$

⇒ $(3y+8)-3y=(7y+11)-3y$

⇒ $8=4y+11$

⇒ $4y+11 = 8$

⇒ $(4y+11)-11 = 8-11$

⇒ $4y= -3$

⇒ $\frac{4}{4}y= \frac{-3}{4}$

⇒ $y= \frac{-3}{4}$

Therefore, value of y which satisfies equation $3y+8=7y+11$ is  $y= \frac{-3}{4}$ .