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8090 [49]
3 years ago
5

In a histogram, are the lengths of the rectangles proportional to the width of the bars?​

Mathematics
2 answers:
mart [117]3 years ago
8 0

Answer:

No

Step-by-step explanation:

Length is the frequency density which is obtained by:

Frequency/width

Height is not proportional to width.

Frequency is proportional to the area of the rectangle

Orlov [11]3 years ago
5 0

Answer:

No

Step-by-step explanation:

In different scenarios, the data will be different. However, sometimes, it's impossible to draw a histogram with equal widths, so in order to maintain clarity and fairness, the area of the bars should actually be proportional to the frequency, which is usually the y-axis of the graph or height of the bars.

Hope this helps!

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Answer:

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Step-by-step explanation:

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antiseptic1488 [7]

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Step-by-step explanation:

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2 years ago
Is 4.95 a terminating decimal
Snowcat [4.5K]

Answer:

Definitely

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Step-by-step explanation:

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3 years ago
Given that sin theta = 1/4, 0
GaryK [48]
Answer: cos(Θ) = (√15) / 4

Explanation:

The question states:

1) sin(Θ) = 1/4

2) 0 < Θ < π / 2

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This is how you solve it.

1) Use the fundamental identity (in this part I use α instead of Θ, just for facility of wirting the symbols, but they mean the same for the case).

(cos \alpha )^2 + (sin \alpha )^2 =1

2) From which you can find:

(cos \alpha )^2 = 1 - (sin \alpha )^2

3) Replace sin(α) with 1/4

=> (cos \alpha )^2 = 1 - (1/4)^2 = 1 - 1/16 = 15/16

=> cos \alpha =+/- \sqrt{15/16} = +/- (\sqrt{15} )/4

4) Given that the angle is in the first quadrant, you know that cosine is positive and the final answer is:

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6 0
4 years ago
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madreJ [45]

Answer:

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Step-by-step explanation:

8 0
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