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3 years ago

How do you solve 2x²-x=3 by factoring

Mathematics

2 answers:

docker41 [41]3 years ago

6 0

The answer for your question is 2x^2-x-3=0
so, by factoring it we have. (2x-3)*(x+1)

Gala2k [10]3 years ago

5 0

Answer:

the value of x are -1 and $\frac{3}{2}$

Step-by-step explanation:

we need to find the factor of 2x²-x=3

subtract both the sides by 3, in above expression

2x²- x - 3 = 3 - 3

2x²- x - 3 = 0

we can write x as -3x + 2x

2x²- 3x +2x - 3 = 0

2x²+ 2x -3x - 3 = 0

take out the common terms,

2x(x+ 1) -3(x +1) = 0

(x+ 1)(2x-3) = 0

If x+ 1 =0

⇒ x = -1

If 2x - 3=0

⇒ $x=\frac{3}{2}$

Therefore, the value of x are -1 and $\frac{3}{2}$

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