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quester [9]
3 years ago
6

How do you solve 2x²-x=3 by factoring

Mathematics
2 answers:
docker41 [41]3 years ago
6 0
The answer for your question is 2x^2-x-3=0
so, by factoring it we have. (2x-3)*(x+1)
Gala2k [10]3 years ago
5 0

Answer:

the value of x are -1 and  \frac{3}{2}

Step-by-step explanation:

we need to find the factor of 2x²-x=3  

subtract both the sides by 3, in above expression

2x²- x - 3 = 3 - 3

2x²- x - 3 = 0

we can write  x as -3x + 2x

2x²- 3x +2x - 3 = 0

2x²+ 2x -3x - 3 = 0

take out the common terms,

2x(x+ 1) -3(x +1) = 0

(x+ 1)(2x-3) = 0

If x+ 1 =0

⇒ x = -1

If 2x - 3=0

⇒ x=\frac{3}{2}

Therefore, the value of x are -1 and  \frac{3}{2}

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