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zlopas [31]
4 years ago
6

1.  What is the domain of the function below?

Mathematics
2 answers:
Nata [24]4 years ago
8 0

<em><u>Question 1:</u></em>

The domain of a function is defined as the input values of the function. Conventionally, they are the values of the x-coordinates of the function.

Therefore, the domain of the given function would be the x-values of the given points.

<u>This means that:</u>

domain is : {0 , 3 , 5 , 8} ................> option B

<em><u>Question 2:</u></em>

For a relation to be a function, each x-value should have one and only one corresponding y-value. Otherwise, it won't be a function.

In the given, we can note that x = 0.3 has two y-values (0.6 and 0.7), <u>therefore</u>, this relation is not a function ...........> option B

Hope this helps :)

Shalnov [3]4 years ago
4 0

The <em><u>correct answers</u></em> are:

#1) {0, 3, 5, 8}; and

#2) no

Explanation:

The domain of a relation is the set of x-coordinates. The x-coordinate of the first ordered pair is 0; of the second ordered pair is 3; of the third ordered pair is 5; and of the last ordered pair is 8. This makes the set {0, 3, 5, 8} for the domain.

A relation is a function if each x-coordinate is mapped to 1 y-coordinate. In this relation, however, we have an x-coordinate that is mapped to more than 1 y-coordinate. 0.3 is mapped to both 0.6 and 0.7; this means the relation is not a function.

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4 years ago
Please Help!
NNADVOKAT [17]
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3 0
4 years ago
What must be true of two rational expressions before they can be added?
VladimirAG [237]

Answer:

They most have common denominators.

Step-by-step explanation:

Let the following two rational expressions:

\frac{p}{a}  , \frac{q}{b}

where p,a,q, b are integers, a and b the denominators are not 0, i.e. a,b\neq 0

We can add rational expressions only if their denominator is same.

That is why we find LCD to be ab.

Then,

\frac{p}{a} +\frac{q}{b} =\frac{pb+qa}{ab}

Let the following two rational expressions:

\frac{p}{a}  , \frac{q}{b}

where p,a,q, b are integers, a and b the denominators are not 0, i.e. a,b\neq 0

We can add rational expressions only if their denominator is same.

That is why we find LCD to be ab.

Then,

\frac{p}{a} +\frac{q}{b} =\frac{pb+qa}{ab}

So, the correct answer is the last option that we can sum rational expressions if they have common denominator.

3 0
4 years ago
Please help me with this
Eduardwww [97]

Answer:

r^{6}

Step-by-step explanation:

Using the rule of exponents

\frac{a^{m} }{a^{n} } = a^{(m-n)} , then

\frac{r^{9} }{r^{3} } = r^{(9-3)} = r^{6}

5 0
3 years ago
What are the coordinates of the point in the directed line segment from (-2,-8) to (5,-1) that partitions the segment into the r
soldier1979 [14.2K]

Answer:

The coordinates of the point P  in the directed line segment from (-2,-8) to (5,-1) that partitions the segment into the ratio of 1 to 6 will be:

  • (x, y) = (-1, -7)

Step-by-step explanation:

Let P be the point.

As the point P is in the directed line segment from (-2,-8) to (5,-1) into the ratio of 1 to 6

i.e.

(x₁, y₁) = (-2,-8)

(x₂, y₂) = (5,-1)

Rise = y₂ - y₁ = -1 - (-8) = -1 + 8 = 7

Run = x₂ - x₁ = 5 - (-2) = 5 + 2 = 7

1 : 6 ratio means the point P lies at

\frac{1}{6+1}=\frac{1}{7}=14\%

Thus,

rise for P = 7 × 14% = 1

run for P =  7 × 14% = 1

Thus, coordinates of P will be:

x = -2 + 1 = -1

y = -8 + 1 = -7

Thus,

The coordinates of the point P  in the directed line segment from (-2,-8) to (5,-1) that partitions the segment into the ratio of 1 to 6 will be:

  • (x, y) = (-1, -7)
4 0
3 years ago
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