Answer:
Use a calculator to divide the two values (small over big) to get 14/35 = 0.4
Now multiply that result by 100 to convert to a percentage
0.4*100 = 40%
he has ridden 40% of the course so
Let f(x) = p(x)/q(x), where p and q are polynomials and reduced to lowest terms. (If p and q have a common factor, then they contribute removable discontinuities ('holes').)
Write this in cases:
(i) If deg p(x) ≤ deg q(x), then f(x) is a proper rational function, and lim(x→ ±∞) f(x) = constant.
If deg p(x) < deg q(x), then these limits equal 0, thus yielding the horizontal asymptote y = 0.
If deg p(x) = deg q(x), then these limits equal a/b, where a and b are the leading coefficients of p(x) and q(x), respectively. Hence, we have the horizontal asymptote y = a/b.
Note that there are no obliques asymptotes in this case. ------------- (ii) If deg p(x) > deg q(x), then f(x) is an improper rational function.
By long division, we can write f(x) = g(x) + r(x)/q(x), where g(x) and r(x) are polynomials and deg r(x) < deg q(x).
As in (i), note that lim(x→ ±∞) [f(x) - g(x)] = lim(x→ ±∞) r(x)/q(x) = 0. Hence, y = g(x) is an asymptote. (In particular, if deg g(x) = 1, then this is an oblique asymptote.)
This time, note that there are no horizontal asymptotes. ------------------ In summary, the degrees of p(x) and q(x) control which kind of asymptote we have.
I hope this helps!
2 - 3 (2x - 5) = 6x + 1
2 -6x +15 = 6x +1 distribute the -3 to (2x -5)
-6x + 17 = 6x + 1 add 2 + 15
16 = 12x add the -6x to the positive 6x and subtract the 1 from 17
1 1/3 = x divide 16/12
Answer:
Jaw saw an average of 6 birds each day
Step-by-step explanation:
Given: One day, Jean saw 7 birds. The next day, she saw 11 birds. The next day, she saw no birds.
To find: average number of birds Jean saw each day
Solution:
Average is a central value of a set of terms.
Average of terms 
is given by 
Number of birds, Jean saw on day one 
= 7
Number of birds, Jean saw on the second one 
= 7
Number of birds, Jean saw on the third one 
= 7
So,
average number of birds Jean saw each day = 
Therefore,
Jaw saw an average of 6 birds each day
65 x 11 I have 2m and a few other people that are not interested to see if they can easily get the best of their time and will
