Answer:
100°= angle b(VERTICAL OPPOSITE ANGLE)
100°+x°=180°[co interior angle]
x=180°-100°
x=80°
Answer:
magnitude = √10
theta=
= -18.435° or 341.565°
Step-by-step explanation:
hmu if u want an explanation. numbers were gotten using desmos
The largest angle is E = 205°.
<h3>
What is a pentagon?</h3>
- A pentagon is any five-sided polygon or 5-gon in geometry.
- A basic pentagon's internal angles add up to 540°.
- A pentagon might be straightforward or self-intersecting.
- A pentagram is a self-intersecting regular pentagon (or a star pentagon).
To find the measure of the largest angle:
The sum of interior angles of a polygon is:
Where n is the number of sides.
Here n = 5, as pentagon has 5 sides.
Let, C = D = x
Then, E = 2x + 15 (15 more than twice C)
We can express the sum of the 5 angles as:
- 60 + 85 + x + x + 2x + 15 = 540
Simplify the left side by collecting like terms:
Subtract 160 from both sides:
- 4x + 160 - 160 = 540 - 160
- 4x = 380
Divide both sides by 4:
- 4x/4 = 380/4 = x = 95
- C = D = x = 95°
- E (2 × 95) + 15 = 205°
The 5 interior angles of the pentagon are:
- 60° + 85° + 95° + 95° + 205° = 540°
The largest angle is E = 205°.
Therefore, the largest angle is E = 205°.
Know more about a pentagon here:
brainly.com/question/25917702
#SPJ4
3/4 ÷ 2/1. Multiply by the reciprocal, 3/4 · 1/2 = 3/8.
Y=x^2+12x+30
8x-y=10
sub x^2+12x+30 for y in the secodn equaiton
8x-(x^2+12x+30)=10
8x-x^2-12x-30=10
-x^2-4x-30=10
times -1
x^2+4x+30=-10
add 10 both sides
x^2+4x+40=0
use quadratic formula
we find that we have 2 imaginary roots and therefor are not on the real plane, they are not plotted on the imaginary plane
no real solution
x=-2+6i or -2-6i
the interseciton on the imaginary plane is
(-2+6i, -26+48i) or (-2-6i,-26-48i)
