Answer:
A.Glycogenesis: Glycogen synthase
B. Glucogenesis: Fructose 1,6 biphosphate phosphatase
C. Urea cycle : Carbamoyl phosphate synthetase
D.Fatty acid synthesis: Acetyl CoA carboxylase
E.Glycolysis : Phosphofructokinase 1
F. Pentose phosphate pathway: Glucose-6-phosphate dehydrogenase
Explanation:
A. Glycogen synthase converts glucose into glycogen during glycogenesis.
B. Fructose 1,6 biphosphate phosphatase catalyzes condensation of dihydroxyacetone phosphate (DHAP) and glyceraldehyde-3-phosphate during glucogenesis.
C. Carbamoyl phosphate synthetase I catalyses production of arbamoyl phosphate during urea cycle.
D. Carboxylase controls fatty acid metabolism.
E. The phosphofructokinase 1 is an important enzyme that regulate formation of two-phosphate sugar molecules during glycolysis.
F. Glucose-6-phosphate dehydrogenase participates in the pentose phosphate pathway. This pathway gives reducing energy to cells.
Dams are not associated with economic advantages.
Dams DO associate with changes to waterway ecosystems, siltation behind the dam, and dam maintenance and breajs,
A membrane bound nucleus (or just a nucleus in general)
Diploid. There has to be 2 existing cells already, in order for it to split into 4
When a cell undergoing cellular division identifies that a chromosome misalignment had taken place the cell cycle stops until the error it's corrected.
Option two of the question states that the cell cycle will <u>proceed uncontrollably, this is not the case for the error at hand</u>. Although this can be a problem for cells and leads to the appearance of cancer, it is not caused by chromosome misalignment. As is the case with options 3 and 4.
The stop or delay in the <u>cell cycle is what normally takes place in these situations.</u> This stoppage is done by the <em><u>spindle checkpoint</u></em>, which prevents <u>duplicate chromosomes from separating.</u>
During this time, the error it's corrected. If a cell is not able to correct the error at this time, many situations can follow. <u>However, the most likely is that the cell will undergo a <em>programmed cellular death.</em> </u>
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