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GREYUIT [131]
3 years ago
10

How to do question 27

Mathematics
1 answer:
GenaCL600 [577]3 years ago
5 0
1/(sin(90 + θ)cos(360 - θ))     -   tan²(-θ)

Note:

 sin(90 + θ) = cosθ        Cosine and Sine are complementary.

cos(360 - θ) = cosθ      Cosine positive in 4th quadrant.

tan(-θ) = -tanθ          Negative angle concept.


1/(sin(90 + θ)cos(360 - θ))     -   tan²(-θ) =  1/(cosθcosθ)     -   (-tanθ)²

                                                                 =  1/(cos²θ)     -       tan²θ

                                                                  =  (1/cosθ)²     -       tan²θ
Note: 1/cosθ = secθ

                                                                 =  (secθ)²     -       tan²θ

                                                                  =  sec²θ     -       tan²θ

                                                                  =  1


Note that    1+ tan²θ = sec²θ is a Trigonometric identity.

That means:  sec²θ     -       tan²θ = 1

Hope this explains it.
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Find a polynomial f(x) of degree 3 that has the following zeros.
Thepotemich [5.8K]

Answer:

f (x) = x (x + 5) (x-9)

Step-by-step explanation:

The zeros of the polynomial are all the values of x for which the function f (x) = 0

In this case we know that the zeros are:

x = 9,\  x-9 =0

x = 0

x = -5, x + 5 = 0

Now we can write the polynomial as a product of its factors

f (x) = x (x + 5) (x-9)

Note that the polynomial is of degree 3 because the greatest exponent of the variable x that results from multiplying the factors of f (x) is 3

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What is the equation of the circle described below. Center (-1, 4), radius = √3
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same problem asked and answered here:


brainly.com/question/3583159





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Firlakuza [10]
The first one shows 1 cm and 7 mm, we need to convert 7 mm to cm
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= 1 cm + \frac{7}{10} cm
= 1 cm + 0.7 cm
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The first one is 1.7 cm

The second one shows 11 inches and 5/16 inches. Between number 11 and 12, there are 16 strips and the pointer lies on fifth strip, thus it show 5/16 inches. The second one is 11\frac{5}{16} inches.

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Find the area bounded by the curve y = x 1/2 + 2, the x-axis, and the lines x = 1 and x = 4 A. 16 B. 10 2/3 C. 7 1/2 D. 28 1/2
jeka94
To find the area of the curve subject to these constraints, we must take the integral of y = x ^ (1/2) + 2 from x=1 to x=4
Take the antiderivative: Remember that this what the original function would be if our derivative was x^(1/2) + 2 
antiderivative (x ^(1/2) + 2) =  (2/3) x^(3/2) + 2x
* To check that this is correct, take the derivative of our anti-derivative and make sure it equals x^(1/2) + 2

To find integral from 1 to 4:
Find anti-derivative at x=4, and subtract from the anti-derivative at x=1
2/3 * 4 ^ (3/2) + 2(4) - (2/3) *1 - 2*1
2/3 (8) + 8 - 2/3 - 2                               Collect like terms
2/3 (7) + 6                                             Express 6 in terms of 2/3
2/3 (7) + 2/3 (9)
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6 0
3 years ago
Pro
Anna11 [10]

Answer:

explain

Step-by-step explanation:

3 0
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