Hello,
$\left \{ {{y= \dfrac{1}{x+2} } \atop {y=x^2+2}} \right. \\\\

 \left \{ {{y= \dfrac{1}{x+2} } \atop {\dfrac{1}{x+2}=x^2+2}} \right. \\\\

 \left \{ {{y= \dfrac{1}{x+2} } \atop {x+2= \dfrac{1}{x^2+2} }} \right. \\\\

 \left \{ {{y= \dfrac{1}{x+2} } \atop {x= \dfrac{1}{x^2+2} -2}} \right. \\\\


$
x=-1.81053571 and y=<span> 5,27803957 </span>

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3 0

2 years ago

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Plss can someone help me

GenaCL600 [577]

I got the answer isa D mate

8 0

3 years ago

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15 fewer than d dogs

Trava [24]