ticket sale on Saturday night is triple the ticket sale on Friday night.
Therefore
ticket sales on Saturday night = 3 x 12425 = 37275
Then
ticket sales for both nights = 12425 + 37275 = 49700
A ticket costs 35.
Let the number of people that attended the carnival on both nights be n.
Then, we have

Therefore 1420 people attended the carnival on both nights
Answer:
Step-by-step explanation:
LET ORANGES=X
PEARS ARE 3 TIMES =3X
LET CHILDREN=Y
IF WE GIVE 5 ORANGES PER CHILD WE NEED 5Y ORANGES.SO THIS =X
X=5Y........................I
IF WE GIVE 8 PEARS PER CHILD WE NEED 8Y PERARS...THERE ARE STILL 21 PEARS LEFT OUT AFTER THIS THAT IS
8Y+21=3X....................II
SUBSTITUTING FOR X FROM EQN.I..
8Y+21=3*5Y
15Y-8Y=21
7Y=21
Y=3
X==5Y=5*3=15..
SO CHILDREN =3
ORANGES=15
PEARS=3*15=45
THANKYOU AND PLEASE AMRK IT BRAINLIEST
Option C:
![$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}](https://tex.z-dn.net/?f=%24%5Cfrac%7B%5Csqrt%5B3%5D%7B100%20x%7D%7D%7B5%7D%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B4%20x%7D%7B5%7D%7D)
Solution:
Given expression is
![$\sqrt[3]{\frac{4 x}{5}}](https://tex.z-dn.net/?f=%24%5Csqrt%5B3%5D%7B%5Cfrac%7B4%20x%7D%7B5%7D%7D)
Note: ![\sqrt[3]{125}=\sqrt[3]{{5^3}} = 5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%3D%5Csqrt%5B3%5D%7B%7B5%5E3%7D%7D%20%20%3D%205)
To find the correct expression for the above simplified expression.
Option A: ![\frac{\sqrt[3]{4 x}}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B4%20x%7D%7D%7B5%7D)
5 can be written as
.
![$\frac{\sqrt[3]{4 x}}{5}=\frac{\sqrt[3]{4 x}}{\sqrt[3]{125} }](https://tex.z-dn.net/?f=%24%5Cfrac%7B%5Csqrt%5B3%5D%7B4%20x%7D%7D%7B5%7D%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B4%20x%7D%7D%7B%5Csqrt%5B3%5D%7B125%7D%20%7D)
![$=\sqrt[3]{\frac{4x}{125} }](https://tex.z-dn.net/?f=%24%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B4x%7D%7B125%7D%20%7D)
It is not the given simplified expression.
Option B: ![\frac{\sqrt[3]{20 x}}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B20%20x%7D%7D%7B5%7D)
![$\frac{\sqrt[3]{20 x}}{5}=\frac{\sqrt[3]{20 x}}{\sqrt[3]{125} }](https://tex.z-dn.net/?f=%24%5Cfrac%7B%5Csqrt%5B3%5D%7B20%20x%7D%7D%7B5%7D%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B20%20x%7D%7D%7B%5Csqrt%5B3%5D%7B125%7D%20%7D)
![$=\sqrt[3]{\frac{20x}{125} }](https://tex.z-dn.net/?f=%24%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B20x%7D%7B125%7D%20%7D)
Cancel the common factor in both numerator and denominator.
![$=\sqrt[3]{\frac{4x}{25} }](https://tex.z-dn.net/?f=%24%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B4x%7D%7B25%7D%20%7D)
It is not the given simplified expression.
Option C: ![\frac{\sqrt[3]{100 x}}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B100%20x%7D%7D%7B5%7D)
![$\frac{\sqrt[3]{100 x}}{5}=\frac{\sqrt[3]{100 x}}{\sqrt[3]{125} }](https://tex.z-dn.net/?f=%24%5Cfrac%7B%5Csqrt%5B3%5D%7B100%20x%7D%7D%7B5%7D%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B100%20x%7D%7D%7B%5Csqrt%5B3%5D%7B125%7D%20%7D)
![$=\sqrt[3]{\frac{100x}{125} }](https://tex.z-dn.net/?f=%24%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B100x%7D%7B125%7D%20%7D)
Cancel the common factor in both numerator and denominator.
![$=\sqrt[3]{\frac{4 x}{5}}](https://tex.z-dn.net/?f=%24%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B4%20x%7D%7B5%7D%7D)
It is the given simplified expression.
Option D: ![\frac{\sqrt[3]{100 x}}{125}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B100%20x%7D%7D%7B125%7D)
![$\frac{\sqrt[3]{100 x}}{125}=\frac{\sqrt[3]{100 x}}{5^3}](https://tex.z-dn.net/?f=%24%5Cfrac%7B%5Csqrt%5B3%5D%7B100%20x%7D%7D%7B125%7D%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B100%20x%7D%7D%7B5%5E3%7D)
It is not the given simplified expression.
Hence Option C is the correct answer.
![$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}](https://tex.z-dn.net/?f=%24%5Cfrac%7B%5Csqrt%5B3%5D%7B100%20x%7D%7D%7B5%7D%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B4%20x%7D%7B5%7D%7D)
Answer:
x = 10°
Step-by-step explanation:
Step 1:
92° + x° + 78° = 180° Supplementary Angles
Step 2:
x° + 170° = 180° Combine Like Terms
Step 3:
x° = 180° - 170° Subtract 170° on both sides
Answer:
x = 10°
Hope This Helps :)