Question

A driver of a car stopped at a gas station to fill up his gas tank. He looked at his watch, and the time read exactly 3:40 p.M. At this time, he started pumping gas into the tank. At exactly 3:44, the tank was full and he noticed that he had pumped 10.2 gallons. What is the average rate of flow of the gasoline into the gas tank?

Answer 1

Answer:

2.55gallons.min

Step-by-step explanation:

given that the initial time before pumping is 3:40 p.M.

after pumping the time reads 3:44, hence he use 4 min to fill his tank

time taken=4 min

also given is that had pumped 10.2 gallons

the capacity of tank= 10.2gallon

Then the average rate of pump is

average rate= capacity of tank/time taken

average rate= 10.2/4min

average rate=2.55gallons.min