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fredd [130]
3 years ago
14

Será a equação x² + 3x = x + 6 + x² do 2º grau?

Mathematics
1 answer:
goblinko [34]3 years ago
3 0

x² + 3x = x + 6 + x²

<u>-x²        </u>    <u>          -x²  </u>

      3x = x + 6

  <u>    -x </u>   <u>-x      </u>

     2x =      6

     \frac{2x}{2} =      \frac{6}{2}

      x =    3

Answer: x = 3

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Answer:

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Step-by-step explanation:

The angles shown are corresponding, meaning that they are equal in measure. To find the answer, set x+25 equal to 55. Solve. x=30.

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What is the diagonal of a right triangle
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Answer:

diagonal of a polygon is a line from a vertex to a non-adjacent vertex. So a triangle, the simplest polygon, has no diagonals. You cannot draw a line from one interior angle to any other interior angle that is not also a side of the triangle.

Step-by-step explanation:

To find the length of the diagonal (or hypotenuse) of a right triangle, substitute the lengths of the two perpendicular sides into the formula a2 + b2 = c2, where a and b are the lengths of the perpendicular sides and c is the length of the hypotenuse. Then solve for c

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3 years ago
What is the outlier in the following data set:<br> 15,11,10,8,9,1,8,7,5,4,2,3, and 37?
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Step-by-step explanation:

The steps to find an outlier:

1. Put the data in numerical order.

2. Find the median.

3. Find the medians for the top and bottom parts of the data. This divides the data into 4 equal parts.

The median with the smallest value is called Q1. The median for all the values - usually just called the median is also called Q2. The median with the largest value is Q3.

4. Subtract...Q3 - Q1. This value is the InterQuartileRange or IQR. Remember that the range means taking the largest minus the smallest. This is a special range having to do with the quartiles.

5. Multiply...1.5 * IQR

6. Take your answer from #5 and do 2 things with it. A). Subtract it from Q1 and B) Additional to Q3.

7. Look at all your data points. If any are SMALLER than Q1 - 1.5 *IQR, they are outliers. If any are LARGER than Q3 + 1.5 *IQR, they are also outliers.

For your data....the median, Q2 is

(43+38)/2 = 40.5.

Q1 = (30+26)/2 = 28.

Q3 = (54+52)/2 = 53

The IQR is 53 - 28 = 25

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Q1 - 37.5 = 28 - 37.5 = -9.5. There is no data value less than -9.5.

Q3 + 37.5 = 53 + 37.5 = 90.5. there is no data value greater than 90.5.

My conclusion is that there are no outliers in this data.

I hope this helps!

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