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Kobotan [32]
3 years ago
13

6.

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
8 0
A. X^4. Hope this helped!
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Easy 5+5+5+5+5+5+555<br><br> this is soo easy<br> answer this for brainiest<br> 2+2+2+22+2+2+22
amm1812

Answer:

585 and 54

Step-by-step explanation:

4 0
3 years ago
The point (3,6) is represented on the graph. Which point also belongs on this graph? (36,72)(35,75)(70,30)(42,85)
anygoal [31]

Answer:

The answer is (36,72)

3 0
3 years ago
Write 0.000038 in scientific notation.
Norma-Jean [14]
0.000038 = 3.8e-5 = 3.8×10⁻⁵ 
8 0
3 years ago
Read 2 more answers
If the diameter of a circle is 9 cm, then its circumference is 56.52 cm.<br><br> True or false?
Brrunno [24]
Circumference 
2*pi*r
2*(22/7)*(9/2)
2*(11/7)*9
198 / 7
28.28 cm

so 56.52 is not correct
3 0
3 years ago
A bag contains 4 red balls, 2 green balls, 3 yellow balls, and 5 blue balls. Find each probability for randomly removing balls w
AfilCa [17]

Answer:

\frac{15}{4802}, \frac{15}{9604}, \frac{9}{2401}, \frac{9}{4802}

Step-by-step explanation:

The bag has a total of (4+2+3+5) = 14 balls. Set up the proportions:

Red: \frac{4}{14}

green: \frac{2}{14}

yellow: \frac{3}{14}

blue: \frac{5}{14}

Now solve!

Removing 1 yellow, 1 red, 1 green, and 1 blue = \frac{3}{14} \cdot \frac{4}{14}  \cdot \frac{2}{14}  \cdot \frac{5}{14} =\frac{15}{4802}

Removing 1 blue, 1 green, 1 green, and 1 yellow = \frac{5}{14} \cdot \frac{2}{14}  \cdot \frac{2}{14}  \cdot \frac{3}{14} =\frac{15}{9604}

Removing 1 red, 1 red, 1 yellow, and 1 yellow = \frac{4}{14} \cdot \frac{4}{14}  \cdot \frac{3}{14}  \cdot \frac{3}{14} =\frac{9}{2401}

Removing 1 green, 1 yellow, 1 yellow, and 1 red = \frac{2}{14} \cdot \frac{3}{14}  \cdot \frac{3}{14}  \cdot \frac{4}{14} =\frac{9}{4802}

4 0
2 years ago
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