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GarryVolchara [31]
3 years ago
11

What is the distance between the points (-4, 2) and (3,-5)?

Mathematics
1 answer:
777dan777 [17]3 years ago
4 0
Solution:
We are going to find the distance between points A -4; 2, B 3; -5 :
d = √ (xb - xa) 2 + (yb - ya) 2 =

= √ (3 - (-4)) 2 + (-5 - 2) 2 =

= √72 + (-7) 2 = √49 + 49 =
= √98
  = 7√2 ≈ 9.899494936611665
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Answer:

Yes, It is a right triangle for the given vertices.

Step-by-step explanation:

Given:

Q(7, –10),

R(–3, 0),

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To Find:

determine whether is a rig ht triangle for the given vertices = ?

Solution:

QR=\sqrt{(-3-7)^2+(0-(-10))^2}

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QR=\sqrt{100+100}

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QR=14.142136

RS=\sqrt{(9-(-3))^2+(-8-0)^2}

RS=\sqrt{(12)^2+(-8)^2}

RS=\sqrt{144+64}

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RS=14.422205

QS=\sqrt{(7-9)^2+(-10-(-8))^2}

QS=\sqrt{(-2)^2+(-2)^2}

QS=\sqrt{4+4}

QS=\sqrt{8}-------------------------------------(3)

QS=2.828427

According to Pythagorean Theorem,

RS^2 = QR^ +QS^2

Substituting the values,

(\sqrt{208})^2 = (\sqrt{200})^2 +(\sqrt{8})^2

208 = 200 +8

208 = 208

Pythagorean theorem is satisfied. Hence it is a right triangle.

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Answer:

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Step-by-step explanation:

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