What is the distance between the points (-4, 2) and (3,-5)?

1 answer:

4 0

Solution:
We are going to find the distance between points A -4; 2, B 3; -5 :
d = √ (xb - xa) 2 + (yb - ya) 2 =

= √ (3 - (-4)) 2 + (-5 - 2) 2 =

= √72 + (-7) 2 = √49 + 49 =
= √98
= 7√2 ≈ 9.899494936611665

You might be interested in

Using the discriminant, how many real number solutions does this equation have? 3x^2 – 2 = 5x

Anvisha [2.4K]

The discriminant of this equation is 49. The solutions for this equation are x=2 and x=- $\frac{1}{3}$
I hope that helps.

7 0

3 years ago

Which of the following expressions is equivalent to a3 + b3?

lubasha [3.4K]

ANSWER
${a}^{3} + {b}^{3} = (a + b)( {a}^{2 } - ab + {b}^{2} )$

EXPLANATION

To find the expression that is equivalent to
${a}^{3} + {b}^{3}$
we must first expand
${(a + b)}^{3}$
Then we rearrange to find the required expression.

So let's get started.

${(a + b)}^{3} = (a + b) {(a + b)}^{2}$

We expand the parenthesis on the right hand side to get,

${(a + b)}^{3} = (a + b) ( {a}^{2} + 2ab + {b}^{2} )$

We expand again to obtain,

${(a + b)}^{3} = {a}^{3} + 3 {a}^{2}b + 3a {b}^{2} + {b}^{3}$

Let us group the cubed terms on the right hand side to get,

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3 {a}^{2}b + 3a {b}^{2}$

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab (a+ b)$

We make the cubed terms the subject,

${(a + b)}^{3} - 3ab (a+ b) = {a}^{3} + {b}^{3}$

We factor to get,

$(a + b)({(a + b)}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We expand the bracket on the left hand side to get,

$(a + b)( {a}^{2} + 2ab + {b}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We finally simplify to get,

$(a + b)( {a}^{2} - ab + {b}^{2} ) = {a}^{3} + {b}^{3}$

5 0

3 years ago

Read 2 more answers

Find the area of the figure

Ket [755]

Answer:

Step-by-step explanation: