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3 years ago

15

MR Arsalan bought a plot of land for rs 108 000 and sold it for a profit of 20% at what price did he sold at

1 answer:

disa [49]3 years ago

6 0

Answer:

The plot of land was sold for rs 129,600

Step-by-step explanation:

The cost of the plot of land = rs 108,000

Profit calculation ( 20% x 108,000) = rs 21,600

Price land was sold = (108,000 + 21,600) = 129,600

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Eight times the sum of 9 and some number is 192.

vovikov84 [41]

Answer:

15

Step-by-step explanation:

To solve this, divide 192 by 8:

192/9 = 24

Subtract 9 from 24:

24 - 9 = 15

Therefore, 8 times the sum of 9 and 15 is 192

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2 years ago

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3 years ago

Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 10 right angle0,−10 in the directions

quester [9]

Solution :

Let $v_0$ be the unit vector in the direction parallel to the plane and let $F_1$ be the component of F in the direction of $v_0$ and $F_2$ be the component normal to $v_0$ .

Since, $|v_0| = 1,$

$(v_0)_x=\cos 60^\circ= \frac{1}{2}$

$(v_0)_y=\sin 60^\circ= \frac{\sqrt 3}{2}$

Therefore, $v_0 = \left$

From figure,

$|F_1|= |F| \cos 30^\circ = 10 \times \frac{\sqrt 3}{2} = 5 \sqrt3$

We know that the direction of $F_1$ is opposite of the direction of $v_0$ , so we have

$F_1 = -5\sqrt3 v_0$

$=-5\sqrt3 \left$

$= \left$

The unit vector in the direction normal to the plane, $v_1$ has components :

$(v_1)_x= \cos 30^\circ = \frac{\sqrt3}{2}$

$(v_1)_y= -\sin 30^\circ =- \frac{1}{2}$

Therefore, $v_1=\left< \frac{\sqrt3}{2}, -\frac{1}{2} \right>$

From figure,

$|F_2 | = |F| \sin 30^\circ = 10 \times \frac{1}{2} = 5$

∴ $F_2 = 5v_1 = 5 \left< \frac{\sqrt3}{2}, - \frac{1}{2} \right>$

$=\left$

Therefore,

$F_1+F_2 = \left< -\frac{5\sqrt3}{2}, -\frac{15}{2} \right> + \left< \frac{5 \sqrt3}{2}, -\frac{5}{2} \right>$

$= = F$

3 0

2 years ago

Find the missing parts of the triangle. Round to the nearest tenth when necessary or to the nearest minute as appropriate.

Katena32 [7]

Answer:

A) A = 27.3°, B = 56.1°, C = 96.6°

Step-by-step explanation:

<u>Use the Law of Cosines:</u>

A = arccos [(b² + c² - a²)/(2bc)] = arccos [(13.2² + 15.8² - 7.3²)/(2*13.2*15.8)] = 27.3°
B = arccos [(a² + c² - b²)/(2ac)] = arccos [(7.3² + 15.8² - 13.2²)/(2*7.3*15.8)] = 56.1°
C = 180° - (A + B) = 180° - (27.3° + 56.1°) = 96.6°

Correct choice is A.

3 0

2 years ago