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aleksley [76]
2 years ago
15

The volume of this right prism is 2,500 ft³. What is the height, x, of the prism? x = ft

Mathematics
1 answer:
Natalka [10]2 years ago
6 0

The height x of the right prism is 10 ft if the volume of this right prism is 2,500 ft³.

<h3>What is a rectangular prism?</h3>

It is defined as the six-faced shape, a type of hexahedron in geometry.

It is a three-dimensional shape. It is also called a cuboid.

From the figure:

Volume = 2500 cubic ft

(10)(x)(25) = 2500

250x = 2500

x = 10 ft

Thus, the height x of the right prism is 10 ft if the volume of this right prism is 2,500 ft³.

Learn more about the rectangular prism here:

brainly.com/question/21308574

#SPJ1

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Which is the solution of the equation 1/4 ( 3x - 1 ) = 2x -2/3
Sever21 [200]

Answer:

x = 1/3 = 0.333

Step-by-step explanation:

Step  1  :

           2

Simplify   —

           3

Equation at the end of step  1  :

  1                       2

 (— • (3x - 1)) -  (2x -  —)  = 0

  4                       3

Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  3  as the denominator :

          2x     2x • 3

    2x =  ——  =  ——————

          1        3  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

2x • 3 - (2)     6x - 2

————————————  =  ——————

     3             3  

Equation at the end of step  2  :

  1                (6x - 2)

 (— • (3x - 1)) -  ————————  = 0

  4                   3    

Step  3  :

           1

Simplify   —

           4

Equation at the end of step  3  :

  1                (6x - 2)

 (— • (3x - 1)) -  ————————  = 0

  4                   3    

Step  4  :

Equation at the end of step  4  :

 (3x - 1)    (6x - 2)

 ———————— -  ————————  = 0

    4           3    

Step  5  :

Step  6  :

Pulling out like terms :

6.1     Pull out like factors :

  6x - 2  =   2 • (3x - 1)

Calculating the Least Common Multiple :

6.2    Find the Least Common Multiple

     The left denominator is :       4

     The right denominator is :       3

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 2 0 2

3 0 1 1

Product of all

Prime Factors  4 3 12

     Least Common Multiple:

     12

Calculating Multipliers :

6.3    Calculate multipliers for the two fraction

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 3

  Right_M = L.C.M / R_Deno = 4

Making Equivalent Fractions :

6.4      Rewrite the two fractions into equivalent fraction

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      (3x-1) • 3

  ——————————————————  =   ——————————

        L.C.M                 12    

  R. Mult. • R. Num.      2 • (3x-1) • 4

  ——————————————————  =   ——————————————

        L.C.M                   12      

Adding fractions that have a common denominator :

6.5       Adding up the two equivalent fractions

(3x-1) • 3 - (2 • (3x-1) • 4)     5 - 15x

—————————————————————————————  =  ———————

             12                     12  

Step  7  :

Pulling out like terms :

7.1     Pull out like factors :

  5 - 15x  =   -5 • (3x - 1)

Equation at the end of step  7  :

 -5 • (3x - 1)

 —————————————  = 0

      12      

Step  8  :

When a fraction equals zero :

8.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -5•(3x-1)

 ————————— • 12 = 0 • 12

    12    

Now, on the left hand side, the  12  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -5  •  (3x-1)  = 0

Equations which are never true :

8.2      Solve :    -5   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

8.3      Solve  :    3x-1 = 0

Add  1  to both sides of the equation :

                     3x = 1

Divide both sides of the equation by 3:

                    x = 1/3 = 0.333

One solution was found :

                  x = 1/3 = 0.333

Processing ends successfully

plz mark me as brainliest :)

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Step-by-step explanation:

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svet-max [94.6K]

x=10

Step-by-step explanation:

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