Answer:
a) The margin of error for a 90% confidence interval when n = 14 is 18.93.
b) The margin of error for a 90% confidence interval when n=28 is 12.88.
c) The margin of error for a 90% confidence interval when n = 45 is 10.02.
Step-by-step explanation:
The t-distribution is used to solve this question:
a) n = 14
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 14 - 1 = 13
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 13 degrees of freedom(y-axis) and a confidence level of
. So we have T = 1.7709
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The margin of error for a 90% confidence interval when n = 14 is 18.93.
b) n = 28
27 df, T = 1.7033

The margin of error for a 90% confidence interval when n=28 is 12.88.
c) The margin of error for a 90% confidence interval when n = 45 is
44 df, T = 1.6802

The margin of error for a 90% confidence interval when n = 45 is 10.02.
1. .1667 or 16%
2. X >_ 2. (Greater than or equal to)
3. X<-1
4. This one isn't an equation, but simplifies to 2x
Answer:
26 percent would be your answer.
Step-by-step explanation:
charging the phone for 1 minute ,it has 2%
i.e,1----->2
After 2 minutes from that time ,i.e total 3 minutes
it has 6% charge
i.e,3--------->6
from the both the above cases ,1 minute provide 2%=6/3
=2
Hence,
for getting 50%charge=50/2
=25 min
and,for 90 %charge=90\2
=45 min