f(x)=4x^3 - 6x^2 + 2x - 5
f(-2)
Replace X with -2:
4(-2)^3 - 6(-2)^2 + 2(-2) - 5 =
Calulate the powers:
4(-8) - 6(4) +(-4) -5=
Multiply:
-32 - 24 -4 -5=
Subtract
-65
x + y = 6 easy medal me plz ? ^^
Answer:
Step-by-step explanation:
the hypothenuse is the largest side in the right triangle
we have 2 side, 7,8
in a right triangle, c^2= a^2+b^2
where c is the hypothenuse
c^2=49+64=113
c=sqrt113=aprox 10.6
so, the answer is no if it has to be exactly 10 ft the hypotenuse
Step-by-step explanation:
98 = 188t - 16t^2
-16t^2 + 188t = 98
-16t^2 + 188t - 98 = 0
8t^2 - 94t + 49 = 0
Use the quadratic formula with a = 8 , b = -94 , c = 49 to get the solutions
t = [(47 - root 1817) / 8]≈ 0.55
and
t = [(47 + root 1817) / 8] ≈ 11.20
Ten-trillion seven billion
