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Bess [88]
3 years ago
9

Jonah can bike 27.2 kilometers in 1 hour. At that rate, how many kilometers can he bike in 15 minutes?​

Mathematics
1 answer:
Wittaler [7]3 years ago
7 0

Answer:6.79999

Step-by-step explanation:

27.2 divided by 60 times 15

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Mark is increasing his exercise routine by running and walking at least 4 miles each day. His goal is to burn a minimum of 1,500
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w + r 》 4 (greater than/equal to 4)

270w + 650r 》 1500

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3 years ago
SOMEONE PLS HELP ME WITH THIS
jolli1 [7]

Answer:

x = 11.25

Step-by-step explanation:

-6 = 0.8x - 15

Add 15 to both sides;

-6 + 15 = 0.8x - 15 + 15

9 = 0.8x

Divide both sides by 0.8;

x = 11.25

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What is the x intercept of y + 4 =− 4(x − 1)
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0

Step-by-step explanation:

since the "b" in y=mx+b ends up being 0, that means that the y intercept is 0, which also means that the x intercept is 0.

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2 years ago
What is y=2x can someone pleas help me
strojnjashka [21]

Answer:

Slope:  2

Step-by-step explanation:

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3 years ago
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Tennis elbow is thought to be aggravated by the impact experienced when hitting the ball. The article "Forces on the Hand in the
Gnoma [55]

Answer:

Step-by-step explanation:

Hello!

The objective is to study whether there is a greater force after impacting on one- handed backhand drive in advanced tennis players than in intermediate tennis players.

Sample 1: Advanced tennis players

X₁: Force (N) on the hand just after impact on a one- handed backhand drive for an advanced tennis player.

n₁= 6

X[bar]₁= 40.29 N

S₁= 11.29

Sample 2: Intermediate players

X₂: Force (N) on the hand just after impact on a one- handed backhand drive for an intermediate tennis player.

n₂= 8

X[bar]₂= 21.40

S₂= 8.30

Assuming that both variables have a normal distribution and both population variances are equal, to compare these two populations is best to do so trough their population means using a t-test for independent samples.

If the force is greater for the advanced players than for the intermediate players, then you'd expect the population mean for the advanced players to be greater than the population mean for the intermediate players:

H₀: μ₁ ≤ μ₂

H₁: μ₁ > μ₂

α: 0.05

t= \frac{(X_[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{5*127.51+7*68.92}{6+8-2} }= 9.66

t_{H_0}= \frac{(40.29-21.40)-0}{9.66\sqrt{\frac{1}{6} +\frac{1}{8} } } = 3.62

Using the p-value approach, the decision rule is

If p-value ≤ α, reject the null hypothesis

If p-value > α, do not reject the null hypothesis

The p-value for this test is 0.00024, it is less than the level of significance, so the decision is to reject the null hypothesis.

This means that at a 5% significance level you can conclude that the average force experienced on the hand after a one-handed backhand drive for advanced players is greater than the average force experienced on the hand after a one-handed backhand drive for intermediate players.

I hope this helps!

3 0
3 years ago
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