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3 years ago

Help me solve this please.

Mathematics

1 answer:

Kazeer [188]3 years ago

5 0

The answer would be D.) 29.8 units

Hope this helps have a great day :)

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Evaluate 16 + 20/t for t =4<br> steps please

Makovka662 [10]

Answer:

Step-by-step explanation:16+20/t, T=4 so its 16 + 20/4, 20/4 is 5, 16+5 = 21.

5 0

2 years ago

Choose the function whose graph is given by

Taya2010 [7]

Answer:

The correct option is D.

Step-by-step explanation:

The given graph is the graph of a cosine function, which shifts 1 unit left.

The cosine function is defined as

$y=a\cos(bx+c)+d$

Where, a is amplitude, b is frequency, c is phase shift and d is vertical shift.

If c>0, then the graph shifts c units left and if c<0, then the graph shifts c units right.

Since the graph show only phase shift and the graph shifts only one unit left, therefore required function is

$y=\cos(x+1)$

Option D is correct.

7 0

3 years ago

Read 2 more answers

54 is 75% of what number?

Furkat [3]

<span>one way to solve this kind of problems is by doing a little bit of reversal 75 % * X = 54 75/100 * X = 54 (we move 75/100 to the right, since it's a fraction the top and bottom number will be reversed) X = 54 * 100/75 X = 5400 / 75 X = 72 Hope I helped! :) Cheers!</span>

3 0

3 years ago

A yard cleanup service charges a $345 fee plus $16.25 per hour. Another cleanup service charges a $213 fee plus $24.50 per hour.

Thepotemich [5.8K]

The time for the job for which the two company are the same is 16

<h3>How to form the equation and find the cost?</h3>

A yard cleanup service charges a $345 fee plus $16.25 per hour. Therefore,

using linear equation,

y = mx + c

where

y = total cost
x = time

Therefore,

y = 345 + 16.25x

Another cleanup service charges a $213 fee plus $24.50 per hour. Therefore,

y = 213 + 24.50x

Hence, the time when both cost are the same is as follows;

213 + 24.50x = 345 + 16.25x

213 - 345 = 16.25x - 24.50x

-132 = -8.25x

x = 132 / 8.25

x = 16

learn more on equation here: brainly.com/question/2072580

4 0

2 years ago

How would I solve this Rational Equation? <br><br>Solve for all values of x.

Nesterboy [21]

9514 1404 393

Answer:

x = 4

Step-by-step explanation:

I like to put these in the form f(x) = 0. We can do that by subtracting the right side. Common factors can be cancelled from numerator and denominator, provided they are not zero.

$\dfrac{7}{x+3}+\dfrac{3}{x-3}-\dfrac{x}{x-3}=0\\\\ \dfrac{7(x-3)+(x+3)(3-x)}{(x+3)(x-3)}=0\\\\\dfrac{(x-3)(4-x)}{(x-3)(x+3)}=0\\\\ \dfrac{4-x}{x+3}=0\qquad x\ne3\\\\x=4 \qquad\text{equate the numerator to zero, add $x$}$

_____

If you leave the numerator as (x-3)(4-x), then there are two values of x that make it zero. Because x=3 makes the equation "undefined", it cannot be considered to be a solution.

4 0

3 years ago