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Ne4ueva [31]
2 years ago
9

Graph the system of equations on graph paper. {8x+6y=482x−3y=−6 Which statements are true about the solution to the system of eq

uations? Select each correct answer.
The x-coordinate of the solution is 3.
The y-coordinate of the solution is 3.
The ordered pair that is the solution to the system lies in Quadrant I .
The y-coordinate of the solution is 4.
The ordered pair that is the solution to the system lies in Quadrant II .
The x-coordinate of the solution is −3 .

PLEASE HELP!!
Mathematics
1 answer:
GuDViN [60]2 years ago
6 0

Answer:

The answers are that the x-coordinate is 3, the y-coordinate is 4 and it is in quadrant I

Step-by-step explanation:

To find these answers, start by solving the system. We can do this by multiplying the second equation by 2 and adding them together.

8x + 6y = 48

4x - 6y = -12

-------------------

12x = 36

x = 3

Next, find the y value by plugging in the x value to either equation and solving.

2x - 3y = -6

2(3) - 3y = -6

6 - 3y = -6

-3y = -12

y = 4

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Answer:

No, 6 hours would cost $335, 35 over her limit of $300.

Step-by-step explanation:

she has to pay $200 plus 22.50 for every hour she rents. So, if she rents for 6 hours, she has to pay $200 + 6(22.50) or $200 + 135=335. She only has $300 so she can’t afford the event.

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2 years ago
One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R
marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

Urn\ 1 = \{B_1, R_1, R_2, R_3\}

Urn\ 2 = \{R_4, R_5, B_2, B_3\}

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

If urn 2 is selected, the following selection exists:

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

<em>See attachment for possibility tree</em>

Solving (b): The total number of outcome

<u>For urn 1</u>

There are 4 balls in urn 1

n = \{B_1,R_1,R_2,R_3\}

Each of the balls has 3 subsets. i.e.

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

So, the selection is:

Urn\ 1 = 4 * 3

Urn\ 1 = 12

<u>For urn 2</u>

There are 4 balls in urn 2

n = \{B_2,B_3,R_4,R_5\}

Each of the balls has 3 subsets. i.e.

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

So, the selection is:

Urn\ 2 = 4 * 3

Urn\ 2 = 12

Total number of outcomes is:

Total = Urn\ 1 + Urn\ 2

Total = 12 + 12

Total = 24

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3 years ago
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: A personal computer manufacturer buys 36% of its chips from Japan and the rest from the United St...
meriva

Answer: 0.9862

Step-by-step explanation:

Given : The probability that the chips belongs to Japan: P(J)= 0.36

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