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Lena [83]
2 years ago
15

A store has a sale with 20% off every item. When you enter the store, you receive a coupon that states that you receive an addit

ional 10% off. Is this equal to a
30% discount? Explain your answer.
Mathematics
1 answer:
mr_godi [17]2 years ago
6 0
No, because let’s say for example that something cost $100.00 so you take 20% (or $20) off of the 100 and you’re left with $80.00. Well then you have your 10% off coupon so you take 10% off of 80, which is 8 dollars. So now you’re at $72.00.

But if we just took off 30% from 100 originally, you would be at $70.00

So no it wouldn’t be the same. If you wanted to check the idea yourself just use different numbers and see if they match at the end.
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\frac{1}{10}

Step-by-step explanation:

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Step-by-step explanation:

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3. Which polynomial is equal to
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Which polynomial is equal to  (-3x^2 + 2x - 3) subtracted from  (x^3 - x^2 + 3x)?

<h3><u><em>Answer:</em></u></h3>

The polynomial equal to (-3x^2 + 2x - 3) subtracted from  (x^3 - x^2 + 3x) is x^3 + 2x^2 + x + 3

<h3><u><em>Solution:</em></u></h3>

Given that two polynomials are: (-3x^2 + 2x - 3) and (x^3 - x^2 + 3x)

We have to find the result when (-3x^2 + 2x - 3) is subtracted from  (x^3 - x^2 + 3x)

In basic arithmetic operations,

when "a" is subtracted from "b" , the result is b - a

Similarly,

When (-3x^2 + 2x - 3) is subtracted from  (x^3 - x^2 + 3x) , the result is:

\rightarrow (x^3 - x^2 + 3x) - (-3x^2 + 2x - 3)

Let us solve the above expression

<em><u>There are two simple rules to remember: </u></em>

  • When you multiply a negative number by a positive number then the product is always negative.
  • When you multiply two negative numbers or two positive numbers then the product is always positive.

So the above expression becomes:

\rightarrow (x^3 - x^2 + 3x) + 3x^2 -2x + 3

Removing the brackets we get,

\rightarrow x^3 - x^2 + 3x + 3x^2 -2x + 3

Combining the like terms,

\rightarrow x^3 -x^2 + 3x^2 + 3x - 2x + 3

\rightarrow x^3 + 2x^2 + x + 3

Thus the resulting polynomial is found

5 0
3 years ago
3 Prove that<br>cos130°+cos 110+ cos10=0​
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We know, cos A + cos B = 2cos(C+D)/2 × cos(C - D)/2

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We know, cos ( 180 - A ) = -cos A

2cos 60 cos 50 - cos 50

Also, cos 60 = 0.5

2×0.5 cos 50 - cos50

cos 50 - cos 50

0  = RHS.

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The answer to the question

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