Question

PLS HELP ME!!!!! Find the sum of the first 100 terms of the arithmetic sequence with the first term 2 and the common difference 5.

Answer 1

Answer:

The sum of the first 100 terms of the arithmetic sequence is 24,950.

Step-by-step explanation:

Sn (sum of the first n terms of an AP) is given by n/2(2a + (n-1)d)

Where

n is the number of terms

a is the first term

d is the common difference

S100 = 100/2(2×2 + (100-1)5) = 50(4 + 99×5) = 50(4 + 495) = 50(499) = 24,950

Answer 2

Answer:

24,950.

Step-by-step explanation:

You can use the arithmetic series formula (a sequence is the list of numbers; a series is the summation of the list).

To find the sum...

(100 / 2) (2 * 2 + (100 - 1)5) = 50 * (4 + 99 * 5) = 50 * (4 + 495) = 50 * 499 = 24950.

Hope this helps!