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ser-zykov [4K]
3 years ago
14

Someone Hellppppp!!!

Mathematics
1 answer:
bekas [8.4K]3 years ago
8 0
It's #2:  20n+100=$180
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the function f(t)= 3,500(1.003)^t gives the value of a saving account t months after it was opened.How long will it take for the
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Answer:

After 19 months,value in the account will reach $3700

Step-by-step explanation:

The value of a savings account f(t) in terms of t ( number of months since account opening) is given as \[3,500(1.003)^{t}\]

We need to determine the value of t when f(t)>=3700

Expressing it in equation form,

\[3,500(1.003)^{t} >= 3700\]

\[=>(1.003)^{t} >= \frac{3700}{3500}\]

\[=>(1.003)^{t} >= 1.057\]

Taking log of both sides,

\[=>t * log(1.003) >= log(1.057)\]

\[=>t >= \frac{log(1.057)}{log(1.003)}\]

\[=>t >= 18.51\]

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