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3 years ago

Which unit should be used when measuring the height of a tall brush

Mathematics

1 answer:

Licemer1 [7]3 years ago

6 0

Answer:

The unit of measurement that should be used is inches

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What is 34 + 56 x 34 and have a great day ?

Kruka [31]

Answer:

1938

Step-by-step explanation:

For this, you will need to use order of operations. You would need to multiply 56 and 34 to get 1904 first, because multiplication comes before addition.

Remember to use PEMDAS.

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2 years ago

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Share £180 in the 4:5

marissa [1.9K]

4 + 5 = 9
£180 / 9 = £20

£20 x 4 = £80
£20 x 5 =£100

Answer:
£80 : £100

hope it helped :)

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2 years ago

Abby will receive a cash prize when she earns 300 bonus points at the videoshop. Abby receives 5 bonus points every time she ren

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2 years ago

If the measure of angle 1 is 78 degrees and the measure of angle 3 is (5x-2)degrees, what is the value of x ?

Dmitriy789 [7]

Answer:

Step-by-step explanation:

Vertical Angles are congruent (equal)

78 = 5x - 2

80 = 5x

16 = x

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2 years ago

Before the pandemic cancelled sports, a baseball team played home games in a stadium that holds up to 50,000 spectators. When ti

spayn [35]

Answer:

(a) $D(x)=-2,500x+60,000$

(b) $R(x)=60,000x-2500x^2$

(d)Optimal ticket price: $12

Maximum Revenue:$360,000

Step-by-step explanation:

The stadium holds up to 50,000 spectators.

When ticket prices were set at $12, the average attendance was 30,000.

When the ticket prices were on sale for $10, the average attendance was 35,000.

(a)The number of people that will buy tickets when they are priced at x dollars per ticket = D(x)

Since D(x) is a linear function of the form y=mx+b, we first find the slope using the points (12,30000) and (10,35000).

$\text{Slope, m}=\dfrac{30000-35000}{12-10}=-2500$

Therefore, we have:

$y=-2500x+b$

At point (12,30000)

$30000=-2500(12)+b\\b=30000+30000\\b=60000$

Therefore:

$D(x)=-2,500x+60,000$

(b)Revenue

$R(x)=x \cdot D(x) \implies R(x)=x(-2,500x+60,000)\\\\R(x)=60,000x-2500x^2$

(c)To find the critical values for R(x), we take the derivative and solve by setting it equal to zero.

$R(x)=60,000x-2500x^2\\R'(x)=60,000-5,000x\\60,000-5,000x=0\\60,000=5,000x\\x=12$

The critical value of R(x) is x=12.

(d)If the possible range of ticket prices (in dollars) is given by the interval [1,24]

Using the closed interval method, we evaluate R(x) at x=1, 12 and 24.

$R(x)=60,000x-2500x^2\\R(1)=60,000(1)-2500(1)^2=\$57,500\\R(12)=60,000(12)-2500(12)^2=\$360,000\\R(24)=60,000(24)-2500(24)^2=\$0$

Therefore:

Optimal ticket price:$12
Maximum Revenue:$360,000

3 0

3 years ago