The sum of any triangle's three angles always add up to 180 degrees. Since you know two angles already ( 37 and 90 ), you can subtract those from 180 to find the remaining angle which is 53 degrees. The answer to your question is 90 degrees and 53 degrees.
Hey there! This is gonna actually be surprisingly simple even though it looks confusing!
Since the scale is perfectly balanced (it's completely flat because the weights are equal) you can use an = sign.
There are 3 cubes which weigh 9 ounces so 3 times 9 is 27 so on the left side you can put down a 27. Then there are 7 circles so so 7x can represent this. So that belongs on the left side as well SO for the left sides we can write this
27 + 7x = _______
Now for the right side. There are 5 cubes so 5 times 9 ounces is 45 so that belongs on the left. And then there is one cube so we can just right x. SO for the right side (combined with the other parts we know looks like this.
27 + 7x = 45 + x
NOW for the solving!
<span>27 + 7x = 45 + x
</span>subtract x from both sides
27 + 6x = 45
subtract 27 from both sides
6x = 18
then divide 6 from both sides
x = 3
So the circles are 3 ounces!!!!
I hope that helps! And feel free to ask me any questions!!
- mathwizzard3
Answer:

Step-by-step explanation:
A exponential function is represented by

where a is the vertical stretch and b is the base and x is the nth
power of x
Since the first number corresponds with zero, that means our y intercept is the first number.
This means when x=0 , y=5 so let find the value of 5.

b to the 0th power equal 1 so


Our equation is for now

Now let plug in 1,30

Divide 5 by both sides

Anything to the 1st power is itself so b equal 6.
So our equation is

Negative 5 is to your left 5 is to your right hope that helps?
Answer:
<em>Answer is </em><em>10</em><em>/</em><em>7</em>
Step-by-step explanation:
[tex] (\frac{6}{10} )r = \frac{6}{7} \\ cancelling \: 6 \: on \: both \: sides \\ (\frac{1}{10} )r = \frac{1}{7} \\ \frac{r}{10} = \frac{1}{7} \\ r = \frac{10}{7} \: \\
<em>HAVE A NICE DAY</em><em>!</em>
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