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3 years ago

Will someone help me with this one I'll give 18 points for help

Mathematics

1 answer:

slamgirl [31]3 years ago

3 0

Back yard- 24.5 x 18= 442
Front yard- 18.5 x 14.5 = 268.25
Other " - 12.5 x 14.5 = 181.25
Total = 890.5 sq ft

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What's the equation of the line that's a perpendicular bisector of the segment connecting C (6, –12) and D (10, –8)? answers: A)

vitfil [10]

Answer:

Step-by-step explanation:

Perpendicular bisector of a line divides the line into 2 equal parts and it is perpendicular to the line.

First let's find the midpoint of CD. The point is where the perpendicular bisector will cut through the line.

midpoint= $( \frac{x1 + x2}{2} , \frac{y1 + y2}{2} )$

Thus, midpoint of CD

$= ( \frac{6 + 10}{2} , \frac{ - 12 - 8}{2} ) \\ = ( \frac{16}{2} , \frac{ - 20}{2} ) \\ = (8, - 10)$

Gradient of line CD

$= \frac{y1 - y2}{x1 - x2} \\ = \frac{ - 12 - ( - 8)}{6 - 10} \\ = \frac{ - 12 + 8}{ - 4} \\ = \frac{ - 4}{ - 4} \\ = 1$

The product of the gradients of perpendicular lines is -1.

gradient if perpendicular bisector(1)= -1

gradient of perpendicular bisector= -1

y=mx +c, where m is the gradient and c is the y-intercept.

y= -x +c

Subst a coordinate to find c.

Since the perpendicular bisector passes through the point (8, -10):

When x=8, y= -10,

-10= -8 +c

c= -10 +8

c= -2

Thus, the equation of the perpendicular bisector is y= -x -2.

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3 years ago

In △ABC, the altitudes from vertices B and C intersect at point M, so that BM = CM. Prove that △ABC is isosceles.

AlekseyPX

Answer:

m∠MBC=m∠MCB by reason base angle theorem

Step-by-step explanation:

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2 years ago

The variables x and y vary inversely. When y is 5, x is 3. What is x when y is 15?

koban [17]

The variables x and y vary inversely. When y is 5 x is 3, so when y is 15 x is 9.

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3 years ago

Raul has been offered three different jobs and must choose which one to accept. One of the factors he is considering is the pay

chubhunter [2.5K]

Answer:

As the pay rate for Job C is the highest, so he must accept the offer from Job C.

Step-by-step explanation:

Given that Raul would work 50 weeks of the year,

40 hours each week,

5 days each week,

and he would receive a 1-hour lunch break each day.

Pay rate for Job A = $35,000 / year

For Job B:

Pay rate = $15 / hour

He will work 40 hours each week.

As he works 5 days a week, so in 1 day he will work 40/5 = 8 hours.

He would receive a 1-hour break each day, for which he will not be paid, so he will receive a payment for 8-1=7 hours.

So, payment for 1 day = $15 x 7 = $105

As he works 5 days a week, so payment for 1 week = $105 x 5 = $525

As he works 50 weeks a year, so payment for 1 year = $525 x 50 = $26250.

So, the pay rate by Job B = $26250 /year

For Job C:

Pay rate = $750 / week

As he works 50 weeks a year, so payment for 1 year = $750 x 50 = $37500.

So, the pay rate by Job C = $37500 /year

As the pay rate for Job C is the highest, so he must accept the offer from Job C.

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2 years ago

In a survey of 603 adults, 98 said that they regularly lie to people conducting surveys. Create a 99% confidence interval for th

marysya [2.9K]

Answer:

The population proportion is estimated to be with 99% confidence within the interval (0.1238, 0.2012).

Step-by-step explanation:

The formula for estimating the population proportion by a confidence interval is given by:

$\hat{p}\pm z_{\alpha /2}\times\sqrt{\frac{\hat{p}\times(1-\hat{p})}{n}}$

Where:

$\hat{p}$ is the sample's proportion of success, which in this case is the people that regularly lie during surveys,

$z_{\alpha /2}$ is the critical value needed to find the tails of distribution related to the confidence level,

$n$ is the sample's size.

First we compute the $\hat{p}$ value:

$\hat{p}=\frac{successes}{n}=\frac{98}{603}=0.1625$

Next we find the z-score at any z-distribution table or app (in this case i've used StatKey):

$z_{\alpha /2}=2.576$

Now we can replace in the formula with the obtained values to compute the confidence interval:

$\hat{p}\pm z_{\alpha /2}\times\sqrt{\frac{\hat{p}\times(1-\hat{p})}{n}}=0.1625\pm 2.576\times\sqrt{\frac{0.1625\times(1-0.1625)}{603}}=(0.1238, 0.2012)$

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3 years ago