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Kitty [74]
3 years ago
8

A stadium has 46,000 seats. Seats sell for ​$30 in Section​ A, ​$24 in Section​ B, and ​$18 in Section C. The number of seats in

Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in ​$1,193,400 from each​ sold-out event. How many seats does each section​ hold?
Mathematics
1 answer:
Dimas [21]3 years ago
3 0
In this question, the number of seat of A equal the number total seats on B and C. The equation would be:

A=B=C
Total seat= A+B+C= A+A+A=3A

The total revenue for the stadium is <span>$1,193,400. Then the total number of the seat would be: 
revenue= total seats*price per seat
</span>$1,193,400= A * $30 + B*24 + C*18
$1,193,400= A * $30 + A*24 + A*18
$1,193,400= A * $72
A= $1,193,400/ 72
A= 16575

Each section hold 16575 seats
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