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3 years ago

Someone help me please. :(

Mathematics

1 answer:

blsea [12.9K]3 years ago

7 0

6x 24 /5 = 68 feet is the sender

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Erin buys 4 packs of potatoes costing £2 each, 2 packs of carrots for £3 per pack, and 5 turnips costing 70p each.

docker41 [41]

She would get £2.50

4 times 2 is 8
2 times 3 is 6
0.7 times 5 is 3.5
Add them together
Minus it from 20
It equals £2.50

8 0

3 years ago

Y=Mx+b and to find the slope

Grace [21]

M is the slope of the equation.

Hope this helps!

5 0

3 years ago

Kevin will take 4 math tests this term. All of tests are worth the same number of points. After taking the first 3 tests, his me

loris [4]

Answer:

Step-by-step explanation:

Kevin would need at least a 96 to raise his mean test score to 90. Hope it helps :)

6 0

3 years ago

I need help with my math assignment

aleksklad [387]

X+15=102
102-15=x
x=87
Please give me brainliest

6 0

3 years ago

The NWBC found that 42.1% of women-owned businesses provided retirement plans contributions.

Natasha_Volkova [10]

Answer:

Sample size of 586 or higher.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

What sample size could be 95% confident that the estimated (sample) proportion is within 4 percentage points of the true population proportion?

Sample size of at least n when $M = 0.04$

42.1% of women-owned businesses provided retirement plans contributions, which means that $p = 0.421$ . So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.421*0.579}{n}}$

$0.04\sqrt{n} = 0.9677$

$\sqrt{n} = \frac{0.9677}{0.04}$

$\sqrt{n} = 24.19$

$\sqrt{n}^{2} = (24.19)^(2)$

$n = 585.2$

We need a sample size of 586 or higher.

3 0

3 years ago