Answer:
1/(72x^11)
Step-by-step explanation:
Multiply like terms and according to rules of exponenets, add exponents which are multiplied. If you have a negative exponent, then put the reciporical of it and you end up with 1/(72x^11).
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16c^2 + 12c
4c(4c + 3) <==
A. To answer this question, we must consider two inequalities. The first inequality we will construct is regarding the number of tickets sold with respect to capacity. The theater cannot exceed the allotted 200 seats, so this would indicate we would use a less than or equal to inequality. The inequality we would construct to illustrate this using adult and child tickets is x + y <= 200.
The second inequality we will construct is based upon the ticket prices set and the theater’s goal. The problem indicates the theater wants to sell “at least $1,500 worth of tickets...” To create the inequality here, we will create it as follows: 12.5x + 6.25y >= 1,500.
To find the intersection point, we must isolate y. In order to do this, move x to the other side of both inequalities. Inequality 2 can be simplified to y >= -12.5x / 6.25 + 1,500 / 6.25. Graph and identify the solution from there.
Answer:
<u>The smaller angle measures 44° and the larger measures 136°</u>
Step-by-step explanation:
Smaller angle = x
Larger angle = 3x + 4
Therefore, we have:
x + 3x + 4 = 180
4x = 180 - 4
4x = 176
x = 176/4
x = 44 ⇒ 3x + 4 = 136
The smaller angle measures 44° and the larger measures 136°
<u>Can I get a brainliest plz?</u>
Answer:
a, Row 1 = 30 seats
Row 2 = 32 seats
Row 3 = 34 seats
Row 4 = 36 seats
b, n + equidistant number of seats added each row (2) * number of row - 1
c, 58 seats
Step-by-step explanation:
a, Because the seats is increasing by 2 after every row after row 1
Therefore, row 2 = row 1 + 2 = 30+2 = 32 seats
Row 3 = Row 2 + 2 =32+2 =34 seats
Row 4 = Row 3 + 2 = 34 + 2 = 36 seats
b, The explicit rule for the number of seats would be:
Row 1 = n
Row 2 = n + equidistant number of seats added each row (2) * (2-1) = n + 2
Row 3 = n+ equidistant number of seats added each row (2) * (3-1) = n+ 4
Row 4 = n + equidistant number of seats added each row(2) * (4-1) = n+6
etc.....
c, The number of seats in the 15th row would be = number of seat in the first row + equidistant number of seats added each row * 15 - 1 (first row)
= 30 + 2 * 14= 30 + 28 = 58 seats
Hope this help you :3
