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Brrunno [24]
3 years ago
7

Joy drew a triangle with one right angle how should she classify this triangle

Mathematics
2 answers:
olganol [36]3 years ago
5 0
She drew a right triangle
jekas [21]3 years ago
4 0
It would be that she drew a right triangle

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According to the table below, what is the probability that a student chosen at random will be 16 or older?
galben [10]

Answer:

probability: 0.44

8 0
3 years ago
Read 2 more answers
1.4t-0.4(t-3.1)=5.8 please help !!
Svetllana [295]
Okay so i cant just post what the answer is i have to type something.
but anyways this is the answer: t= 4.56
4 0
3 years ago
Enter an expression for the perimeter of the given figure. Simplify the expression.
dlinn [17]

Answer:

4x + 28.4 in.

Step-by-step explanation:

perimeter = sum of lengths of sides

perimeter = x + 2 + x + 2 + x + 2 + x + 2 + 10.2 + 10.2

perimeter = 4x + 28.4

3 0
2 years ago
Eve is making a bird house. To make the walls she takes a piece of wood and cuts it into 4 pieces in the ratio 5:6:6:7. The long
allsm [11]

Answer:

The original piece of wood is 108 cm

Step-by-step explanation:

From the given ratio, the shortest is of the ratio 5 and the longest is of the ratio 7

Let the original piece of wood be x

so the sum of the ratios will be;

5 + 6 + 6 + 7 = 24

the shortest length would be 5/24 * x

= 5x/24

the longest will be 7/24 * x = 7x/24

From the question;

7x/24 -5x/24 = 9

(7x-5x) = 24(9)

2x = 24(9)

x = (24 * 9)/2

x = 108 cm

4 0
3 years ago
50 students live in a dormitory. The parking lot has the capacity for 30 cars. Each student has a car with probability 12 , inde
Maurinko [17]

Answer:

P(X is greater than 30) = 0.06

Step-by-step explanation:

Given that:

Sample proportion (p) = 0.5

Sample size = 30

The Binomial can be approximated to normal with:

\mu = np = 50 \times 0.5 \\ \\ \mu= 25

\sigma = \sqrt{np(1-p) } \\ \\  \sigma = \sqrt{50 \times (0.5)(1-0.5) } \\ \\ \sigma = 3.536

To find:

P(X> 30)

So far we are approximating a discrete Binomial distribution using the continuous normal distribution. 30 lies between 29.5 and 30.5

Normal distribution:

x = 30.5, \mu = 25, \sigma = 3.536

Using the z test statistics;

z = \dfrac{x - \mu}{\sigma}

z = \dfrac{30.5 - 25}{3.536}

z = \dfrac{5.5}{3.536}

z = 1.555

The p-value for P(X>30) = P(Z > 1.555)

The p-value for P(X>30) = 1 - P (Z< 1.555)

From the z tables;

P(X> 30) = 1 - 0.9400

Thus;

P(X is greater than 30) = 0.06

7 0
3 years ago
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