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ra1l [238]
3 years ago
11

To find the height of a mountain, surveyors often find the angle of elevation to the top from two points at the same altitude a

fixed distance apart. Suppose that the angles of the elevation from two points 500 meters apart are 35.333333333 degrees and 25.766666666666 degrees. How high is the mountain above the altitude of the two points

Mathematics
1 answer:
8090 [49]3 years ago
5 0

Answer:

756.36 meters

Step-by-step explanation:

Draw a diagram.  Let's call the horizontal distance from the top of the mountain to the closest point x.

Using tangent = opposite / adjacent, we can write two equations:

tan 35.3° = h / x

tan 25.76° = h / (x + 500)

Solve for x in the first equation and substitute into the second.

x = h / tan 35.3°

tan 25.76° = h / ((h / tan 35.3°) + 500)

Solve for h.

tan 25.76° (h / tan 35.3°) + 500 tan 25.76° = h

500 tan 25.76° = h (1 − (tan 25.76° / tan 35.3°))

500 tan 25.76° tan 35.3° = h (tan 35.3° − tan 25.76°)

h = 500 tan 25.76° tan 35.3° / (tan 35.3° − tan 25.76°)

h ≈ 756.36 meters

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Answer:

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Now that we have the length of AD, we can find the length of AB. The right triangle \triangle ADB is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio x:x\sqrt{3}:2x, where x is the side opposite to the 30 degree angle and 2x is the length of the hypotenuse.

Since AD is the hypotenuse, it must represent 2x in this ratio and since AB is the side opposite to the 30 degree angle, it must represent x in this ratio (Derive from basic trig for a right triangle and \sin 30^{\circ}=\frac{1}{2}).

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