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3 years ago

Help me please, and example

Mathematics

1 answer:

cricket20 [7]3 years ago

8 0

Answer:

Step-by-step explanation:

i think its c

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What is this: 4810 ÷ 13?

natali 33 [55]

Answer:

370

Step-by-step explanation:

6 0

3 years ago

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An architect is designing a house in which a 104 square foot room and a 130 square foot room share a wall what is the greatest p

Alla [95]

Both rooms share a common side whose dimension is unknown. Call it x.

Then, the area of both squares have x as common factor.

So, x is the greatest common factor of 104 and 130.

You should know how to calculate the greatest common factor of two integers.

Just find the prime factors and choose the common factors raised to the lowest exponent.

104 = (2^3) (13)

130 = (2) (5)(13)

=> the greatest common factor is 2 * 13 = 26, and that is the greatest possible integer length of the shared wall.

Answer: 26

8 0

3 years ago

If 2^21 = x + 2^20, what is the value of x ?

andrew-mc [135]

Answer:

x = 1048576

Step-by-step explanation:

4 0

4 years ago

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Jerry's Seed Palace claims that 80% of its lima bean seeds will germinate. Suppose the company's claim is true. Callie buys a pa

Mekhanik [1.2K]

Answer:

Step-by-step explanation:

This is a Bernoulli trial problem.

Since the probability that the seed will germinate is 80% or 0.8, the probability that they won’t germinate is 0.2

Now let’s say the probability to germinate is p and the probability not to is a, we can now set up the Bernoulli equation in this regard. Since we are proposing that exactly 14 will germinate, it means 6 are not expected to germinate

P(14) = 20C14 (0.8)^14 (0.2)^6 = 0.109099700973

Option A is the right answer

3 0

3 years ago

Which is the value of this expression when p=-2 and q=-1?

saul85 [17]

Answer:

D. 4

Step-by-step explanation:

$[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4$

8 0

3 years ago