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viktelen [127]
3 years ago
14

Help me please, and example

Mathematics
1 answer:
cricket20 [7]3 years ago
8 0

Answer:

Step-by-step explanation:

i think its c

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Drag the expressions into the boxes to correctly complete the table.
lora16 [44]

Answer:

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

Step-by-step explanation:

The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form ax^n.

Here:

n = non-negative integer

a = is a real number (also the the coefficient of the term).

Lets check whether the Algebraic Expression are polynomials or not.

Given the expression

x^4+\frac{5}{x^3}-\sqrt{x}+8

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains \sqrt{x}, so it is not a polynomial.

Also it contains the term \frac{5}{x^3} which can be written as 5x^{-3}, meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression x^4+\frac{5}{x^3}-\sqrt{x}+8 is not a polynomial.

Given the expression

-x^5+7x-\frac{1}{2}x^2+9

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.

Given the expression

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!

Given the expression

\left|x\right|^2+4\sqrt{x}-2

is not a polynomial because algebraic expression contains a radical in it.

Given the expression

x^3-4x-3

a polynomial with a degree 3. As it does not violate any condition as mentioned above.

Given the expression

\frac{4}{x^2-4x+3}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

3 0
3 years ago
If the least value of n is 5, which inequality best shows all the possible values of n?
Lostsunrise [7]
N is greater than or equal to 5. (n <u>></u> 5)

5 0
3 years ago
-3 1/2=1/2 x+1/2 x+x simplified?
Elina [12.6K]
-3 1/2 = 1/2x + 1/2x + x
- 7/2 = 2x
(-7/2) / 2 = x
-7/2 * 1/2 = x
- 7/4 (or - 1 3/4) = x
4 0
3 years ago
The question is on the picture included
Alexxx [7]
The next step is to draw an arc with center E.

4 0
3 years ago
What is the quadratic in vertex form that has a vertex of (-1, 5)<br><br> Options in image
dimaraw [331]

Answer:

Third option

y = (x+1) ^ 2 + 5

Step-by-step explanation:

In this case we must write a quadratic equation in the vertex form.

We have the vertice. (-1, 5)

We know that the vertex form for a quadratic equation is:

y = (x-h) ^ 2 + k.

Where (h, k) is the vertex.

So if the vertex is (-1, 5), the equation sought is:

y = (x-(-1)) ^ 2 + 5

y = (x+1)) ^ 2 + 5

Therefore the answer is the Third option.

5 0
3 years ago
Read 2 more answers
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