Part I
The weight of the truck without cargo is 22150+11300= 33450 pound
The weight of the cargo is given as
and altogether with the weight of the truck, the sum must not exceed 75500
The inequality is given
Part II
Hence, the maximum weight allowed for the cargo is 42050 pounds
y= -4x and 8x-y=6
what you do is switch the negative y to the other side and move the positive 6 to the other side thus making y=8x-6.
I don't get what those numbers are on the question but the way you solve it is by combining them and putting one y into the other
8x-6=-4x 12x=6 6/12=x .5=x
then you plug in x to find y in whichever equation:
-4x=y -4(.5)=y -2=y
so the final answer would be (.5,-2)
Answer:
3%×300,=900
900÷100=9
Step-by-step explanation:
answer is 9
Answer:
.5
Step-by-step explanation:
Sin(x)cos(y) + cos(x)sin(y) = sin(x+y)
sin(17+13) = 1/2
Answer:
1 solution
Step-by-step explanation:
y = 1/2x + 4
x + 2y = -8
Solve the second equation for y.
2y = -x - 8
y = -1/2x - 4
The two equations in slope-intercept form are:
y = 1/2x + 4
y = -1/2x - 4
The system consists of two lines with different slopes, so they intercept at a single point which is the solution.
Answer: 1 solution