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irinina [24]
3 years ago
14

The concrete truck is up to 23 tons about how many pounds is the truck

Mathematics
1 answer:
nadezda [96]3 years ago
4 0
The answer is 46000
because 1 ton is 2000 pounds and I did 2000 * 23
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On analyzing a function, John finds that f(a) = b. This means that the graph of f passes through the point
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Answer choice A is correct
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F(x). = x3+2x2+9x+18 find all zeros and use synthetic division
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F(x)= (x-2) (x2-9) = (x-2)(x-3)(x+3)
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2 years ago
-(a-b)(a-bc) if a=3 b=-4 and c=2
Oxana [17]

Answer:

-77

Step-by-step explanation:

Simply plug in: -(3-(-4))(3-(-4)(2))

Because the "-" sign is outside the parentheses, you would distribute.

It would then be: -3-4. *positive and negative=negative, negative and negative=positive. -3-4=-7. It would then be: (-7) · ((3-(-4)(2))

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6 0
3 years ago
Read 2 more answers
The number of entrees purchased in a single order at a Noodles & Company restaurant has had an historical average of 1.7 ent
SOVA2 [1]

Answer:

t=\frac{2.1-1.7}{\frac{1.01}{\sqrt{48}}}=2.744    

p_v =P(t_{(47)}>2.744)=0.0043  

If we compare the p value and the significance level given \alpha=0.02 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is higher than 1,7 entrees per order at 2% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=2.1 represent the mean

s=1.01 represent the sample standard deviation

n=48 sample size  

\mu_o =1.7 represent the value that we want to test

\alpha=0.02 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 1.7, the system of hypothesis would be:  

Null hypothesis:\mu \leq 1.7  

Alternative hypothesis:\mu > 1.7  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{2.1-1.7}{\frac{1.01}{\sqrt{48}}}=2.744    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=48-1=47  

Since is a one side test the p value would be:  

p_v =P(t_{(47)}>2.744)=0.0043  

Conclusion  

If we compare the p value and the significance level given \alpha=0.02 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is higher than 1,7 entrees per order at 2% of signficance.  

4 0
3 years ago
Read 2 more answers
X-1) x-x-2x+8<br> Long division
Nastasia [14]

Answer:

Ummm

Step-by-step explanation:

Im confused

4 0
2 years ago
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