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3 years ago

13

For the standard form of two billion three Hundred fifty thousand four Danielle wrote 2,350,400,000 what error did she make what

is the correct standard form of the number

1 answer:

Leona [35]3 years ago

7 0

I believe the correct answer is 2,300,500,004

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Susan walks 2 kilometers during each trip to school how many trips will susan have to make in all to walk a total of 4 kilometer

Genrish500 [490]

Answer:

2

Step-by-step explanation:

2 km per trip x 2 trips = 4 km

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3 years ago

Determine the solution set for the inequality statement? + 4 < 9 y > -10 y < -10 y > - 5/2 y < - 5/2

Igoryamba

Answer:

Sorry im not sure on this one...

Step-by-step explanation:

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2 years ago

The line a bus arrives at the bus stop every 25 minutes and the line B bus arrives every 15 minutes. Both are at the bus stop ri

Tpy6a [65]

They will be there for 40 minutes because 25+15 is 40

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3 years ago

What is 0.0000981 in scientific notation?

tatiyna

9.81 or 98.1 pretty sure it's the first one

3 0

2 years ago

Diano4ka-milaya [45]

Answer:

$\huge\boxed{\sqrt[4]{16a^{-12}}=2a^{-3}=\dfrac{2}{a^3}}$

Step-by-step explanation:

$16=2^4\\\\a^{-12}=a^{(-3)(4)}=\left(a^{-3}\right)^4\qquad\text{used}\ (a^n)^m=a^{nm}\\\\\sqrt[4]{16a^{-12}}=\bigg(16a^{-12}\bigg)^\frac{1}{4}\qquad\text{used}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\=\bigg(2^4(a^{-3})^4\bigg)^\frac{1}{4}\qquad\text{use}\ (ab)^n=a^nb^n\\\\=\bigg(2^4\bigg)^\frac{1}{4}\bigg[(a^{-3})^4\bigg]^\frac{1}{4}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=2^{(4)(\frac{1}{4})}(a^{-3})^{(4)(\frac{1}{4})}=2^1(a^{-3})^1=2a^{-3}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}$

$=2\left(\dfrac{1}{a^3}\right)=\dfrac{2}{a^3}$

5 0

3 years ago