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harkovskaia [24]
2 years ago
10

Which relation is a direct variation that contains the ordered pair (2, 7)?

Mathematics
1 answer:
Tasya [4]2 years ago
8 0
Lets write equation of a function:

y = kx + n

Direct variation in simple is equation of a line which has n=0 or in other words which y to x ratio is k.

First option gets 7=7 but it isnt direct variation because n is not equal to 0

third option is indeed correct. once we implement coordinates (2,7) we get 7=7

Answer is 
y = 7/2x
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A new vehicle is worth $2500. If it depreciates records in value 12% per year, after 6 years what will it be worth
Margaret [11]

Answer:

Step-by-step explanation:

2500 - 12%

12% of 2500 = 300

2500 - 300 = 2200

12% of 2200 = 264

2200-264=1936

Repeat another 4 times

8 0
3 years ago
Esmeralda rent a car from a company that race cars by an hour she has a pair nishal fee of $52 and then they charged her $8 per
tatuchka [14]

Answer:

11 hours is the most she can afford

Step-by-step explanation:


7 0
3 years ago
Suppose we have 3 cards identical in form except that both sides of the first card are colored red, both sides of the second car
Nikolay [14]

Answer:

probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3

Step-by-step explanation:

First of all;

Let B1 be the event that the card with two red sides is selected

Let B2 be the event that the

card with two black sides is selected

Let B3 be the event that the card with one red side and one black side is

selected

Let A be the event that the upper side of the selected card (when put down on the ground)

is red.

Now, from the question;

P(B3) = ⅓

P(A|B3) = ½

P(B1) = ⅓

P(A|B1) = 1

P(B2) = ⅓

P(A|B2)) = 0

(P(B3) = ⅓

P(A|B3) = ½

Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;

P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]

Thus;

P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]

P(B3|A) = (1/6)/(⅓ + 0 + 1/6)

P(B3|A) = (1/6)/(1/2)

P(B3|A) = 1/3

5 0
3 years ago
A sinusoidal carrier wave has an amplitude of 5 volts, a frequency of 1MHz, and zero phase angle. Select the correct carrier wav
Vedmedyk [2.9K]

Answer:

The correct answer is b.

Step-by-step explanation:

The wave equation is given generally as:

c(x, t) = Acos(kx - wt)

Where A = amplitude

k = wave number

w = angular frequency.

x = horizontal distance moves by the wave.

t = time

The options show to us that the wave depends only on t and not (x, t).

Hence, the wave equation becomes:

c(t) = Acos(wt)

Given that:

A = 5 V

f = 1 * 10⁶ Hz

Angular Frequency, w, is given as:

w = 2πf

w = 2 * π * 1 * 10⁶ Hz

w = 2π(1 * 10⁶)

The wave equation becomes:

c(t) = 5cos(2*π*1*10⁶)

The correct answer is b.

6 0
3 years ago
Please help! I will mark as brainliest IF answer is right. <3
kramer

Step-by-step explanation:

Domain x belongs to [-4 , 0]

Range y belongs to [-4 , 4]

6 0
3 years ago
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