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timofeeve [1]
4 years ago
6

If 2^(x+3) - 2x = k(2^x) what is the value of k

Mathematics
1 answer:
svlad2 [7]4 years ago
8 0

Answer:

\large\boxed{C)\ 7}

Step-by-step explanation:

Use:

a^n\cdot a^m=a^{n+m}

2^{x+3}-2^x=2^x\cdot2^3-2^x=8\cdot2^x-2^x=(8-1)\cdot2^x=7\cdot2^x\\\\2^{x+3}-2^x=k(2^x)\\\\7\cdot2^x=k(2^x)\Rightarrow k=7

8\cdot2^x-2^x=8\cdot2^x-1\cdot2^x=(8-1)(2^x)=7\cdot2^x\\\\\text{distributive property:}\ a(b-c)=ab-ac

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You'll basically complete the square for two equations at the same time. Set it up like this:

(16x^2 + 96x) + (9y^2 - 18y) = 9

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then complete the square by taking the second term of each polynomial, dividing by two, and squaring it.

For instance the first one will be 6/2 = 3^2 = 9

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Add these to numbers to the polynomials as well as to the other side of the equation to keep it equal. You should end up with this.


(x^2 + 6x+9) + (y^2 - 2y+1) = (9/144)+9+1

Then find a common denominator on the right side of the equals sign and add them all together to get:

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the center of the circle is (-3,1) according to the factored out polynomials and the radius will be the square root of the number on the right side of the equals sign = sqrt(1449/144) = 3.17
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