Answer:
b=−1/14ot+2
Step-by-step explanation:
Let's solve for b.
to−8+5b=−6+26−9b
Step 1: Add 9b to both sides.
ot+5b−8+9b=−9b+20+9b
ot+14b−8=20
Step 2: Add -ot to both sides.
ot+14b−8+−ot=20+−ot
14b−8=−ot+20
Step 3: Add 8 to both sides.
14b−8+8=−ot+20+8
14b=−ot+28
Step 4: Divide both sides by 14.
14b
14
=
−ot+28
14
b=
−1
14
ot+2
Answer:
The answer to the question is
The kinds of polygons that could be Diedre's quadrilateral are rectangle and square
Step-by-step explanation:
We note the conditions of the polygon as thus
Number of sides = 4, Which include trapezoid, square, rectangle
Size of angles = 90 ° which eliminates trapezoid
Sizes of opposite sides = Equal opposite sides, includes square and rectangle
With the above we conclude that the possible polygons in Diedre's quadrilateral are rectangle and square
301/750=
.401333333333
The tenth place is where the 4 is.
It will be .4 meters long.
I hope this helps!
~kaikers
1,4,5,6 the b value of the y-intercept
