Answer:
The smaller number is 22
The larger number is 30
Step-by-step explanation:
L + S = 52
L = S + 8
Set both equations equal to L.
S + 8 = -S + 52
+S +S
2S + 8 = 52
- 8 - 8
2S = 44
S = 22
To find the larger number, plug 22 in as S into the equations.
L = 30
Answer:
x = approx. 1.24 or -7.24
Step-by-step explanation:
It's hard to factor directly so we should use the quadratic formula or complete the square. I'm going to go with completing the square.
x²+6x-9=0
x²+6x=9
x²+6x is the same as x²+2·3·x, in order to make this into the algebraic identity (A+B)²=A²+2AB+B², we must add B², or in this case 3² to both sides. (A is x, B is 3)
x²+6x+9=18
(x+3)²= 18
x+3= ±√18
x= ±4.24 -3 (approximately 4.24)
First solution for x = 4.24-3 = 1.24
Second solution for x = -4.24-3 = -7.24
There are 7 keys in each octave (C,D,E,F,G,A and B) so it would make sense to divide 52 to 7.
52/7=7 octaves and 3 extra kets
Answer:
P = 2000 * (1.00325)^(t*4)
(With t in years)
Step-by-step explanation:
The formula that can be used to calculated a compounded interest is:
P = Po * (1 + r/n) ^ (t*n)
Where P is the final value after t years, Po is the inicial value (Po = 2000), r is the annual interest (r = 1.3% = 0.013) and n is a value adjusted with the compound rate (in this case, it is compounded quarterly, so n = 4)
Then, we can write the equation:
P = 2000 * (1 + 0.013/4)^(t*4)
P = 2000 * (1.00325)^(t*4)