<u>Answer:</u>
Given below.
<u>Explanation:</u>
Coordinates given: W( -4, -3 ) , X( 1 , -2 ), Y(2, -7 ) , Z( -3, -8)
To find the distance we will use the formula: distance=√((x2-x1)²+(y2-y1)²)
WX = √((1--4)²+(-2--3)²)
= √26
YZ = √((-3-2)²+(-8--7)²)
= √26
XY = √((2-1)²+(-7--2)²)
= √26
WZ = √(-3--4)²+(-8--3)²
= √26
WY = √(2--4)²+(-7--3)²
= 2√13
XZ = √(-3-1)²+(-8--2)²
= 2√13
y=cos(x)+2
What is the amplitude of the function?
What is the period of the function?
I believe -7 + 91i. i hope this helps
Answer:
The height above sea level at <em>B</em> is approximately 1,604.25 m
Step-by-step explanation:
The given length of the mountain railway, AB = 864 m
The angle at which the railway rises to the horizontal, θ = 120°
The elevation of the train above sea level at <em>A</em>, h₁ = 856 m
The height above sea level of the train when it reaches <em>B</em>, h₂, is found as follows;
Change in height across the railway, Δh = AB × sin(θ)
∴ Δh = 864 m × sin(120°) ≈ 748.25 m
Δh = h₂ - h₁
h₂ = Δh + h₁
∴ h₂ ≈ 856 m + 748.25 m = 1,604.25 m
The height above sea level of the train when it reaches <em>B</em> ≈ 1,604.25 m
Answer:
x= -3
Step-by-step explanation:
x equals to -3 is the standard form