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Genrish500 [490]
3 years ago
12

A truck can be rented from Company A for ​$70 a day plus ​$0.50 per mile. Company B charges ​$20 a day plus ​$0.60 per mile to r

ent the same truck. Find the number of miles in a day at which the rental costs for Company A and Company B are the same.
Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
7 0

Answer:

The rental cost for Company A and Company B will be the same after 500 miles

Step-by-step explanation:

The total cost of renting a truck from Company A can be expressed as;

Total rental cost(Company A)=Cost per day+Total rate

where;

Cost per day=70

Total rate=rate per mile×number of miles (m)=(0.5×m)=0.5 m

replacing;

Total rental cost(Company A)=70+0.5 m...equation 1

2. The total cost of renting a truck from Company B can be expressed as;

Total rental cost(Company B)=Cost per day+Total rate

where;

Cost per day=20

Total rate=rate per mile×number of miles (m)=(0.6×m)=0.6 m

replacing;

Total rental cost(Company B)=20+0.6 m...equation 2

Equating equation 1 to equation 2

70+0.5 m=20+0.6 m

0.6 m-0.5 m=70-20

0.1 m=50

m=50/0.1

m=500 miles

The rental cost for Company A and Company B will be the same after 500 miles

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Answer:

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Step-by-step explanation:

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Plug the numbers in to get x:35

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17/10=x/35

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Step-by-step explanation:

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3 years ago
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A farmer raises only ducks and pigs. There are 55 animals in all on his farm, and 146 legs.
nordsb [41]

Answer:

Number of ducks = 37

Number of pigs = 18

Step-by-step explanation:

Let,

x be the number of ducks

y be the number of pigs

According to given statement;

x+y=55     Eqn 1

2x+4y=146     Eqn 2 (As ducks will have 2 legs and pigs will have 4)

Multiplying Eqn 1 by 2

2(x+y=55)

2x+2y=110    Eqn 3

Subtracting Eqn 3 from Eqn 2

(2x+4y)-(2x+2y)=146-110

2x+4y-2x-2y=36

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Dividing both sides by 2

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Putting y=18 in Eqn 1

x+18=55

x = 55-18

x = 37

Hence,

Number of ducks = 37

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On 1st January 2020, Laurie invests P dollars in an account that pays a nominal annual interest rate of 5.5%, compounded quarter
andrezito [222]

Answer:

1) The common ratio =  1.055

2) The year in which the amount of money in Laurie's account will become double is the year 2032

Step-by-step explanation:

1) The given information are;

The date Laurie made the investment = 1st, January, 2020

The annual interest rate of the investment = 5.5%

Type of interest rate = Compound interest

Therefore, we have;

The value, amount, of the investment after a given number of year, given as follows;

Amount in her account = a, a × (1 + i), a × (1 + i)², a × (1 + i)³, a × (1 + i)ⁿ

Which is in the form of the sum of a geometric progression, Sₙ given as follows;

Sₙ = a + a × r + a × r² + a × r³ + ... + a × rⁿ

Where;

n = The number of years

Therefore, the common ratio = 1 + i = r = 1 + 0.055 = 1.055

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2) When the money doubles, we have;

2·a = a × rⁿ = a × 1.055ⁿ

2·a = a × 1.055ⁿ

2·a/a = 2 = 1.055ⁿ

2 = 1.055ⁿ

Taking log of both sides gives;

㏒2 = ㏒(1.055ⁿ) = n × ㏒(1.055)

㏒2 = n × ㏒(1.055)

n = ㏒2/(㏒(1.055)) ≈ 12.95

The number of years it will take for the amount of money in Laurie's account to double = n = 12.95 years

Therefore, the year in which the amount of money in Laurie's account will become double = 2020 + 12..95 = 2032.95 which is the year 2032

The year in which the amount of money in Laurie's account will become double = year 2032.

3 0
3 years ago
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