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Viktor [21]
3 years ago
15

Amber completed a 25-kilometer road race in 3 hours. She ran at the same speed and covered the same distance each hour. Between

which 2 whole numbers does the distance she ran each hour lie? Draw a visual model to find the distance she ran each hour.
You don’t have to do the last part but it’d be great if you did
Mathematics
1 answer:
pishuonlain [190]3 years ago
4 0
To answer this question, you will find the number of kilometers she ran per hour.  This is called the unit rate.  To get the unit rate, you will divide the number of kilometers by the number of hours, so 25/3.  The answer is 8 1/3 kilometers per hour. This number falls between the whole numbers 8 and 9.  I will describe to you how to create a visual model to show this.  If you draw a long bar and break it into 25 equal sections.  Take 24 of these groups and circle 3 groups of 8 to show the 8 km.  Take the last group and break it into 3 equal sections as well (creating groups the size of 1/3). One of these goes with the group of 8 you got when you broke the whole sections into groups of three creating the mixed number 8 1/3 kilometers.  This shows you modeling the 25 km broken into 3 equal sized groups (which is division).
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Given a standard deck of 52 cards, 3 cards are dealt without replacement. Using this situation, answer the questions below.&lt;b
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Given that <span>3 cards are dealt without replacement in a </span><span>standard deck of 52 cards.

Part A:

There are 4 queens in a standard deck of 52 card, thus the probability that the first card is a queen is given by 4 / 52 = 1 / 13.

Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given</span> by 3 / 51 = 1 / 17

Similarly the probability that the third card is a queen is given by 2 / 50 = 1 / 25.

Therefore, the probability that <span>all three cards are queens is given by

\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} = \frac{1}{5525}



Part B:

Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.



Part C:

Given that the first card is a queen, then there are 3 queens remaining out of 51 cards remaining, thus the number of cards that are not queen is 51 - 3 = 48 cards.

Therefore, </span>if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17



Part D:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.

Therefore, </span>if two of the three cards are queens ,<span>the probability that you will be dealt three queens</span> is given by 2 / 50 = 1 / 25 = 0.04



Part E:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining, thus the number of cards that are not queen is 50 - 2 = 48 cards.

Therefore, </span>if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96
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