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4 years ago

15

Jesse is solving the equation x2−10x=2

1 answer:

Fofino [41]4 years ago

3 0

C, 25. You take half of the variable B, so 5 in this case, because B=10. Then you square it. 5^2 is 25.

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PLEASE HELP!!!!!

Arte-miy333 [17]

Part A: Yes this is a function because there are no repeated x values. Each x value points to exactly one y output. You can graph each point and the graph will not fail the vertical line test.

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Part B: Plug x = 6 into the f(x) function given to get
f(x) = 7x-15
f(6) = 7*6-15
f(6) = 42-15
f(6) = 27
Now compare this with the table. According to the table, when x = 6, the value of y is 14. So the f(x) value is larger than the table value when x = 6

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Part C:

Replace f(x) with 6 and solve for x

f(x) = 7x-15
6 = 7x-15
6+15 = 7x-15+15
21 = 7x
7x = 21
7x/7 = 21/7
x = 3

So the final answer, for part C, is x = 3

5 0

4 years ago

Drag the correct word and the appropriate value to the box with each given interval

pashok25 [27]

Answer:

this answer is for functional value only

6 0

3 years ago

For an independent t-test, if the mean of group 1=10, mean of group 2=12, ss1 =5, ss2=8, there are 6 individuals per group. what

eimsori [14]

The value of t obtained is 4.76

Given,

Mean of group 1, $M_{1}$ = 10

Mean of group 2, $M_{2}$ = 12

$SS_{1}$ = 5

$SS_{2}$ = 8

Number of individuals per group, n = 6

The degrees of freedom are calculated as:

$df = (n_{1} -1)+(n_{2} -1)$ = ( 8-1) + (8-1) = 7 + 7 = 14

The difference between sample means $M_{d}$ is:

$M_{d}$ = $M_{1} -M_{2}$ = 10 - 12 = 2

Here n is equal for both groups which is = 8

Now,

The standard deviation of sample 1 :

$s_{1} =\sqrt{\frac{SS_{1} }{n_{1} -1} } = \sqrt{\frac{5}{8-1} } = \sqrt{\frac{5}{7} } = 0.85$

The standard deviation of sample 2 :

$s_{2}= \sqrt{\frac{SS_{2} }{n_{2}-1 } } = \sqrt{\frac{8}{8-1} } = \sqrt{\frac{8}{7} } = 1.07$

Now, we have to calculate the standard error for the difference of the means.

MSE = $\frac{(n_{1}-1)s^{2} _{1}+(n_{2}-1)s^{2} _{2} }{(n_{1}-1)+(n_{2}-1) }$

= $\frac{(8-1)(0.85^{2})+(8-1)(1.07^{2}) }{(8-1)+(8-1)}$

= $\frac{10.1318}{14}$

MSE = 0.7237

Then, the standard error can be calculated as:

$s_{M_{d} } = \sqrt{\frac{2MSE}{n} } = \sqrt{\frac{2 * 0.7237}{8} } = 0.42$

Now we can calculate t :

$t=\frac{M_{d} }{s_{M_{d} } } = \frac{2}{0.42} = 4.76$

Learn more about standard deviation here : brainly.com/question/16403666

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7 0

2 years ago

Hello I need help with this math provlem

Katyanochek1 [597]

Answer:

i am sorry

Step-by-step explanation:

i sorry

4 0

3 years ago

Create a word problem for the 5-d process

kolbaska11 [484]

Answer:

every day i had to dig D amount of times minus 5 hours for break

Step-by-step explanation:

8 0

3 years ago