Answer:
8x^2+5y+1
Step-by-step explanation:
1+x^2-3+2y+7x^2+3+3y
Combine like terms
x^2+7x^2+2y+3y+3+1-3
8x^2+5y+1
Volume of the cube with side 4p = 4p x 4p x 4p = 64p³
Volume of the cube with side 2q² = 2q² x 2q² x 2q² = 8q⁶
Total Volume = 64p³ + 8q⁶
Total Volume = (4p)³ + (2q²)³
Total Volume = (4p + 2q²)( ( 4p)² - (4p)(2q²) + (2q²)²)
Total Volume = (4p + 2q²)( 16p² - 8pq² + 4q⁴)
Answer: (4p + 2q²)( 16p² - 8pq² + 4q⁴)
Answer:
In order to subtract fractions, there must be a common denominator (the number on the bottom of the fraction). 7 and 3 can be multiplied to get 21 (a common factor). To get each fraction to have a denominator of 21, they can be multiplied by 3 and 7 respectively and then subtracted. Attached is an image of the problem worked out. I apologize for the messy handwriting. Hope this helps!
Step-by-step explanation: