this should help I have it step
1) x= 2
6x2+10=22
2) x = 2
6x2-4=4x2
F(x)=2x-5
k(x)=f(x+3)=2(x+3)-5=2x+6-5=2x+1
k(x)=2x+1
Answer:
There are 38 premium tickets and 82 regular tickets in a pile.
Step-by-step explanation:
Given,
Total number of tickets = 120
Total amount = $5812
Solution,
Let the number of premium tickets be x.
And the number of regular tickets be y.
Total number of tickets is the sum of total number of premium tickets and total number of regular tickets.
So the equation can be written as;

Again,total amount is the sum of total number of premium tickets multiplied by cost of each premium ticket and total number of regular tickets multiplied by cost of each regular ticket.
So the equation can be written as;

Now We will multiply equation 1 by 25 we get;

Now Subtracting equation 3 from equation 2 we get;

We will now substitute the value of x in equation 1 we get;

Hence There are 38 premium tickets and 82 regular tickets in a pile.
Answer:
Each tray has 5 colours and one of the colour on the tray is purple. Hence 1/5 of the colours on the tray is purple and thus 1/5 of the colours on the 20 trays is purple. The fraction of colours on the trays will not change. If written out logically, 20 purples out of 100 colours in total on the trays will also given the fraction 1/5.