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solniwko [45]
3 years ago
10

Find the degree of the polynomial: a^3+3a^2−5a

Mathematics
1 answer:
emmainna [20.7K]3 years ago
3 0

Answer:

The degree of the polynomial is 3

Step-by-step explanation:

Given:

a^3+3a^2-5a

To Find:

The degree of the polynomial= ?

Solution:

The degree of the polynomial   is the value of the greatest exponent of any expression (except the constant ) in the polynomial. To find the degree all that you have to do is find the largest exponent in the polynomial

Here in the given polynomial

a^3+3a^2- 5a

The terms are

a^3

3a^2

5a

The term  a^3 has  the largest exponent of  3

Note:  The degree of the polynomial does not depend  on coefficients of the terms

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Evgen [1.6K]

this should help I have it step

5 0
3 years ago
1.<br> Solve.<br> 6x + 10 = 22<br> 2.<br> Solve.<br> 6x - 4 = 4x<br> What is the answers
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1) x= 2
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2) x = 2
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3 0
4 years ago
If ​f(x)equals 2xminus5 and ​k(x)equals ​f(xplus3​), write the equation for​ k(x).
ololo11 [35]
F(x)=2x-5
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7 0
3 years ago
There are premium tickets costing $99 each and rest are regualr tickets costing $25 each. A pile of 120 tickets have a total val
polet [3.4K]

Answer:

There are 38 premium tickets and 82 regular tickets in a pile.

Step-by-step explanation:

Given,

Total number of tickets = 120

Total amount = $5812

Solution,

Let the number of premium tickets be x.

And the number of regular tickets be y.

Total number of tickets is the sum of total number of premium tickets and  total number of regular tickets.

So the equation can be written as;

x+y=120\ \ \ \ \ equation\ 1

Again,total amount  is the sum of total number of premium tickets multiplied by cost of each premium ticket and  total number of regular tickets multiplied by cost of each regular ticket.

So the equation can be written as;

99x+25y=5812\ \ \ \ equation\ 2

Now We will multiply equation 1 by 25 we get;

x+y=120\\25(x+y)=120\times25\\25x+25y= 3000 \ \ \ \ equation\ 3

Now Subtracting equation 3 from equation 2 we get;

(99x+25y)-(25x+25y)=5812-3000\\\\99x+25y-25x-25y=2812\\\\74x=2812\\\\x=\frac{2812}{74}=38

We will now substitute the value of x in equation 1 we get;

x+y=120\\38+y=120\\y=120-38\\y=82

Hence There are 38 premium tickets and 82 regular tickets in a pile.

3 0
3 years ago
2. Ms. Groves has trays of paints for students in her
olga55 [171]

Answer:

Each tray has 5 colours and one of the colour on the tray is purple. Hence 1/5 of the colours on the tray is purple and thus 1/5 of the colours on the 20 trays is purple. The fraction of colours on the trays will not change. If written out logically, 20 purples out of 100 colours in total on the trays will also given the fraction 1/5.

4 0
3 years ago
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