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lapo4ka [179]
3 years ago
14

Solve the Equation x^5-5x^3+4x=0

Mathematics
1 answer:
aev [14]3 years ago
8 0

Answer:

x = 2 or x = 1 or x = 0 or x = -1 or x = -2

Step-by-step explanation:

Solve for x:

x^5 - 5 x^3 + 4 x = 0

The left hand side factors into a product with five terms:

x (x - 2) (x - 1) (x + 1) (x + 2) = 0

Split into five equations:

x - 2 = 0 or x - 1 = 0 or x = 0 or x + 1 = 0 or x + 2 = 0

Add 2 to both sides:

x = 2 or x - 1 = 0 or x = 0 or x + 1 = 0 or x + 2 = 0

Add 1 to both sides:

x = 2 or x = 1 or x = 0 or x + 1 = 0 or x + 2 = 0

Subtract 1 from both sides:

x = 2 or x = 1 or x = 0 or x = -1 or x + 2 = 0

Subtract 2 from both sides:

Answer:  x = 2 or x = 1 or x = 0 or x = -1 or x = -2

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4(12+3+9) as an distribute expression
miss Akunina [59]

Answer:

Step-by-step explanation: multiply 4 by 12 then 4 by 3 then 4 by 9.

6 0
3 years ago
PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198
Elena-2011 [213]

The weight in 1980 is \frac{4k}{5} kilograms

<em><u>Solution:</u></em>

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

<em><u>To find: weight in 1980</u></em>

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

<em><u>The percentage increase is given by formula:</u></em>

\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

<em><u>Substituting the values in formula,</u></em>

25 = \frac{k-x}{x} \times 100\\\\25x = 100(k-x)\\\\x = 4(k-x)\\\\x = 4k - 4x\\\\5x = 4k\\\\x = \frac{4k}{5}

Thus the weight in kilograms in 1980 is \frac{4k}{5}

7 0
3 years ago
How many solutions does s^2 -35=-35 have​
Alexandra [31]

Answer:

1 solution

Step-by-step explanation:

s² - 35 = -35

Add 35 to both sides: <em>s² = 0</em>

<em>s can only be 0, and 0 has no positives nor negatives</em>, so one number.

4 0
3 years ago
Read 2 more answers
A television transmitter tower is 400 feet high. if the angle between the guy wire (attached at the top) and the tower is 51.8°,
vova2212 [387]
Let the length of the guy wire be x feet.
cos 51.8 = 400/x
x = 400/cos 51.8 = 646.82 feet.
The answer is 646.82 feet.
8 0
3 years ago
Is 500 is 10 times as much as 50
12345 [234]
Yes, since 50 x 10 = 500.
8 0
3 years ago
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