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3 years ago

Solve the Equation x^5-5x^3+4x=0

Mathematics

1 answer:

aev [14]3 years ago

8 0

Answer:

x = 2 or x = 1 or x = 0 or x = -1 or x = -2

Step-by-step explanation:

Solve for x:

x^5 - 5 x^3 + 4 x = 0

The left hand side factors into a product with five terms:

x (x - 2) (x - 1) (x + 1) (x + 2) = 0

Split into five equations:

x - 2 = 0 or x - 1 = 0 or x = 0 or x + 1 = 0 or x + 2 = 0

Add 2 to both sides:

x = 2 or x - 1 = 0 or x = 0 or x + 1 = 0 or x + 2 = 0

Add 1 to both sides:

x = 2 or x = 1 or x = 0 or x + 1 = 0 or x + 2 = 0

Subtract 1 from both sides:

x = 2 or x = 1 or x = 0 or x = -1 or x + 2 = 0

Subtract 2 from both sides:

Answer: x = 2 or x = 1 or x = 0 or x = -1 or x = -2

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The temperature at noon at a ski resort is 3 F . The temperature drops 8 F by midnight what is the temperature at midnight

tester [92]

-5F because 3-8= -5

6 0

3 years ago

Hich ordered pair is the solution to the system of equations? {x=(1)/(2)y+5} {2x+3y=-14}

faltersainse [42]

Answer:

(2, - 6 )

Step-by-step explanation:

Given the 2 equations

x = $\frac{1}{2}$ y + 5 → (1)

2x + 3y = - 14 → (2)

Substitute x = $\frac{1}{2}$ y + 5 into (2)

2( $\frac{1}{2}$ y + 5 ) + 3y = - 14 ← distribute and simplify left side

y + 10 + 3y = - 14

4y + 10 = - 14 ( subtract 10 from both sides )

4y = - 24 ( divide both sides by 4 )

y = - 6

Substitute y = - 6 into (1) for corresponding value of x

x = (0.5 × - 6 ) + 5 = - 3 + 5 = 2

Solution is (2, - 6 )

8 0

3 years ago

Read 2 more answers

Which expression is equivalent to 2(x -1)+x

olchik [2.2K]

$\huge\text{Hey there!}$

$\huge\textbf{Question reads....}$

$\large\text{Which expression is equivalent to 2(x - 1) + x?}$

$\huge\textbf{Step by step to find your result}$

$\large\textbf{First you have to DISTRIBUTE 2 WITHIN the}\\\large\textbf{PARENTHESES}$

$\large\text{2(x - 1) + x}\\\rightarrow\large\text{2(x) + 2(-1) + x}\\\rightarrow\large\text{2x - 2 + x}\\\rightarrow\large\text{2x - 2 + 1x}\\\rightarrow\large\textbf{COMBINE the LIKE TERMS}\leftarrow\\\rightarrow\large\text{(2x + 1x) - (2)}\\\rightarrow\large\text{3x - 2}$

$\huge\textbf{FINALLY WE HAVE YOUR RESULT}$

$\huge\boxed{\textsf{Therefore, your answer is: }}}\\\huge\boxed{\mathsf{Option\ B. \ 3x - 2}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy }\\\huge\text{your day!}$

<h2>~ $\frak{Amphitrite1040:)}$ </h2>

5 0

2 years ago

Read 2 more answers

Use the tangent identity to

Lunna [17]

Answer:

$tan(x)=\frac{44\sqrt{89}}{89}$

Step-by-step explanation:

tan is defined as: $tan(x)=\frac{opposite}{adjacent}$

sin is defined as: $sin(x)=\frac{opposite}{hypotenuse}$

cos is defined as: $cos(x)=\frac{adjacent}{hypotenuse}$

We can also define tan as: $tan(x)=\frac{sin(x)}{cos(x)}$

because plugging in the definitions of sin and cos in we get: $tan(x)=\frac{(\frac{opposite}{hypotenuse})}{(\frac{adjacent}{hypotenuse})}\\\\tan(x)=\frac{opposite}{hypotenuse}*\frac{hypotenuse}{adjacent}\\\\tan(x)=\frac{opposite}{adjacent}$

which you'll notice is the original definition of tan(x)

So using this definition of tan(x) we can use the givens sin(x) and cos(x) to find tan(x)

$sin(x)=\frac{44}{45}\\\\cos(x)=\frac{\sqrt{89}}{45}\\\\tan(x)=\frac{sin(x)}{cos(x)}$

plugging in sin(x) and cos(x) we get:

$tan(x)=\frac{\frac{44}{45}}{\frac{\sqrt{89}}{45}}\\\\tan(x)=\frac{44}{45}*\frac{45}{\sqrt{89}}\\\\tan(x)=\frac{44}{\sqrt{89}}$

We usually don't like square roots in the denominator, and from here we want to rationalize the denominator which we do by removing the square root from the denominator.

We can do this by multiplying the fraction by: $\frac{\sqrt{89}}{\sqrt{89}}$ which doesn't change the value of the fraction since it simplifies to 1, but it gets rid of the square root in the denominator

$tan(x)=\frac{44}{\sqrt{89}}*\frac{\sqrt{89}}{\sqrt{89}}\\\\tan(x)=\frac{44\sqrt{89}}{89}$

5 0

1 year ago

What is the constant term in the expression 6x^3y + 8x^2 + 5x + 7? (Input a numeric value only.) (3 points)

Zinaida [17]

The constant term is 7. this is because x and y are unknowns and change depending on the other. As 6x^3y will change depending on what x or y is so will: 8x^2 and 5x therefore 7 is the constant term.

7 0

3 years ago