Answer:
cccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
Step-by-step explanation:
In place of t, or theta, I'm going to utilize x instead. So the equation is -3*cos(x) = 1. Get everything to one side and we have -3*cos(x)-1 = 0
Let f(x) = -3*cos(x)-1. The goal is to find the root of f(x) in the interval [0, 2pi]
I'm using the program GeoGebra to get the task done of finding the roots. In this case, there are 2 roots and they are marked by the points A and B in the attachment shown
A = (1.91, 0)
B = (4.37, 0)
So the two solutions for theta are
theta = 1.91 radians
theta = 4.37 radians
The answer is a because it is open circle
Answer:
-a^2 + -a + 12
Step-by-step explanation:
Expand the following:
(3 - a) (a + 4)
(3 - a) (a + 4) = (3) (a) + (3) (4) + (-a) (a) + (-a) (4):
-a a + 3 a - 4 a + 3 4
3×4 = 12:
-a a + 3 a - 4 a + 12
-a a = -a^2:
-a^2 + 3 a - 4 a + 12
Grouping like terms, -a^2 + 3 a + 4 (-1) a + 12 = -a^2 + (3 a - 4 a) + 12:
-a^2 + (3 a - 4 a) + 12
3 a - 4 a = -a:
Answer: -a^2 + -a + 12
Answer:
-7
Step-by-step explanation:
y=3x-7
x=0 ⇒ y= 3*0-7= -7