Answer:
Number 1
Step-by-step explanation:
The median in number 1 is 13 and the range for number 1 is also thirteen so it has to be it.
Answer:
145 yd²
Step-by-step explanation:
There will be dour triangular faces. For a triangle, area is given as
A=½bh where b is base and h is height. The base will be 5 yards and h is 12 yards hence for one triangular face, area will be ½*5*12=30 yd²
Since they are four similar triangles, area of triangular faces will be 30*4=120 yd²
The surface area of a square base is given by
A=a*a=a² where a is the dimension of one side. Given that the meaurement is 5 yards then A=5²=25 yd²
Total area will be the sum of triangular and square faces hence 120+25=145 yd²
Answer:
−
8
5
=−0.62500
Step-by-step explanation:
I used something Imao-
Answer:
The width of the yard is 20 ft
Step-by-step explanation:
In this particular question, we are asked to calculate the width of the rectangular front yard given the area of the front yard and the length of the front yard.
Mathematically, the area of the front yard is calculated by multiplying the length of the front yard by the breadth of the front yard.
Let’s say A = L * W
Substituting the known values, the unknown width would thus be:
W = A/L = 600 sq.ft / 30ft
W = 20 ft
To factor out you have to think what multiples to AC and adds to B.
Ax^2+Bx+C
So... for this problem AxC=1x-24 or -24
B is -2.
So what two numbers multiply to -24: -3x8, -8x3, -4x6, -6x4, -2x12, -12x2.
Out of these, which adds to -2: -6+4=-2.
So the factors are (d-6)(d+4)
OR the longer way, which you really only use if A is not equal to 1.
Use the terms above and then rewrite the equation with two middle terms: d^2+4d-6d-24
Group the terms by using addition: (d^2+4d)+(6d-24)
Find what they have in common and factor it out. For the first, it's d. They both have d. So: d(d+4)
To check this, distribute the d. It should equal the first set lf parenthesis.
For the second, they have a number in common. 6 is a multiple of 24 so you can take that out: -6(d+4)
If the terms inside the parenthesis are the same, that's good. It means we can pair the insides and the outsides together to form the factors.
The two terms outside the parenthesis: d, -6 group together and become (d-6)
The inside terms stay the same: (d+4)
(d-6)(d+4)
Again, this is the longer way and no necessary for a problem like this. But if it was 2d^2, then this would be perfecf.